Recent content by ProjectENIS

Hi again ehild, I added in the arbitrary constant and got the equation! Thank you so much! Regarding the V = RC (dV/dt), I have misunderstood the derivation, and assumed that it is a general formula for all RC circuits. Thanks for pointing that out, I'll read up on it tonight. Once again...

Sorry for the mistake, That will get me (V - (r/[R+r])V0)-1dV = [-(r/[R+r])RC)]-1dt Which gets me ln [V - (r/[R+r])V0)] = t/(RrC/[R+r]) V - (r/[R+r])V0) = e(t/(RrC/[R+r])] And a little rearranging gets me V = e(t/(RrC/[R+r])] + (r/[R+r])V0) Hmm, did i do something wrong? Even if I subsitute...

Hi ehild, Thanks for your reply. For the differential equation, V = RC (dV/dt), solved for V = e-t/(RC) + k, e-t/(RC) + k = RC (dV/dt) dV/dt = e-t/(RC) + k/RC Is this what you meant?

Homework Statement Given a circuit with two resistors, R and r, and a capacitor of C, and EMF of V0 as shown in the diagram, find the voltage across the capacitor during charging. Prove that this voltage, V is given by V = V0 (r/(R+r)) (1-e-((R+r)t)/(RrC)) Homework Equations N.A...