Hi again ehild, I added in the arbitrary constant and got the equation! Thank you so much!
Regarding the V = RC (dV/dt), I have misunderstood the derivation, and assumed that it is a general formula for all RC circuits. Thanks for pointing that out, I'll read up on it tonight.
Once again...
Sorry for the mistake,
That will get me
(V - (r/[R+r])V0)-1dV = [-(r/[R+r])RC)]-1dt
Which gets me ln [V - (r/[R+r])V0)] = t/(RrC/[R+r])
V - (r/[R+r])V0) = e(t/(RrC/[R+r])]
And a little rearranging gets me V = e(t/(RrC/[R+r])] + (r/[R+r])V0)
Hmm, did i do something wrong? Even if I subsitute...
Hi ehild,
Thanks for your reply.
For the differential equation, V = RC (dV/dt), solved for V = e-t/(RC) + k,
e-t/(RC) + k = RC (dV/dt)
dV/dt = e-t/(RC) + k/RC
Is this what you meant?
Homework Statement
Given a circuit with two resistors, R and r, and a capacitor of C, and EMF of V0 as shown in the diagram, find the voltage across the capacitor during charging. Prove that this voltage, V is given by V = V0 (r/(R+r)) (1-e-((R+r)t)/(RrC))
Homework Equations
N.A...