Recent content by psmarz

Find the vertical component of the velocity and find the horizontal component of the velocity. With the vertical component you can find out how long it takes for the ball to reach maximum height, where vf = 0 Then find out how high it rises and add the initial height from which it was thrown...

Thank you for helping me figure it out.

(35 sin) 25 = 14.3 They did it by subtracting 35 from 90 and doing (55 cos)25 = 14.3

Thank you for the visual. I am new to the whole SOH, CAH, TOA and that visual helps greatly... C = 25m/s B = 20.5m/s A = 14.3

Ok I do not get how the angel with the horizontal is 35 while the vertical is 55 because you aimed 35 degree upward.

Homework Statement The ball is now thrown with the same speed at an angel of 35 deg upward. How far does it travel? My question is... They have vhor = (25 m/s) cos 35 deg = 20.5 m/s and The angel with the vertical is (90 - 35) = 55 deg so... vvert = (25 m/s) cos 55 deg = 14.3 It seems...

Remember SOH, COH, TOA

The ASVAB is broken down into different areas. General Science, Arithmetic Reasoning, Word Knowledge, Paragraph Comprehension, Auto Shop Info, Mathematics Knowledge, Mechanical Comp, Electrical Information. You want to have a high AFQT score with is the average of AR+WK+PC+MK Also to qualify...

You could also look at the Navy Nuclear Program. It would be easy to get a engineering technologist degree almost by the time you get out and with going through the navy nuke program you would be very sought after in the job market. Just a thought.

Thank you...lol...good thing about me getting stuck on this equation... A) Now I know what these variables mean... B) Memorized some formulas lol I will try making up some problems later and solve in 2 steps... It has been sooo long since I messed with math or anything.

Ok so it is 0.8 = 9.8t2+(.5)(-9.8)(t2 0.8 = 4.9t2 .163 = t2 .4 = t0 = v0 - 9.8(.4) 0 = v 0 - 3.92 3.92 = v0Now all I need is more than this one problem to practice lol...you are awesome, thank you, thank you, thank you.

Ya...I have that down...but I am having a problem...lets see... vf= v0 + at so 0 = v0+9.8t or am I doing gravity wrong? Cause I solved for v0 and moved over to the other equation... 0.8 = -9.8t2 + .5(9.8)(t2) .8 = -9.8t2 + 4.9t2 (Now if I already have not made an error with a...

ooo thank you so much for laying out what the variables mean...let me see what I can do now...Let me try and have a crack at this again.

Homework Statement In order for a volleyball player to jump vertically upward a distance of 0.8 meters, his initial velocity must be?Homework Equations s=v0t + .5at2 vf= v0 + atThe Attempt at a Solution I missed the question the other day on a practice and it has been forever since I messed...

Well mainly I am trying to study up for the Mechanical Comp portion of the ASVAB and if I do not score high enough in the various areas I will need to better understanding of basic physics for the NAPT test. It is basic physics (acceleration, gravity, forces, 3 laws of Newton, etc)