Recent content by ptlffrty

Here we go, I think I got it. the two equations: I1 - I2 = .02A (KCL top center node) 240I1 + 100I2 = 9V (KVL outer loop) => I1 = 20.59mA => I2 = 40.59mA => VR3 = I2 * R3 = 40.59 * 100 = 4.06V

What's going wrong now? 240Ω*I1 = 20ma*100Ω ==> I1 = (20mA*100Ω)/240Ω I1 = 8.33mA 9v + 100Ω*I2 = 20ma*100Ω ==> I2 = [(20mA*100Ω)-9]/100Ω I2 = -70mA I1 + I2 =/= 20

I'm confused again. How do I solve for the i1 and i2? sum of the voltages in a loop = 0, so for loop 1 with current i1 on the eft: v1 + v2 = 0 i1*r1 + i1*r2 = 0 i1*240 + i1*100 = 0 loop 2 with current i2 on right: v2 + v3 = 0 i2*r2 + i2*r3 = 0 i2*100 + i2*100 = 0 I know I'm...

Homework Statement solve for voltage V with polarity as shown. Homework Equations KCL - current into a node = current out The Attempt at a Solution I tried to do nodal analysis using the top center node as v. v/240 + (v-9)/100 - 20mA - v/100 = 0 => v=26.4V Obviously, I'm...

added the moment of inertia of the hoop (mr^2) witht he moment of inertia of the disk (.5mr^2).. good chance its wrong, but itdoesnt really matter at this point, i just turned the assignment in a few minutes ago

torque and moment of inertia question.. https://www.physicsforums.com/showthread.php?t=103825" can anyone help me out?

anyone? anyone?

bump bump bump

oops. i meant disk.

Deleted Deleted