Recent content by punyhuman92

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    Ball and Ramp. Kinetic Energy. Friction.Angular Momentum and Velocity.

    Homework Statement http://landau.physics.fsu.edu/capstick/teaching/2048C-Fall11/Final/Spring09.pdf Homework Equations U_g= mgh K.E=1/2mv^2 + 1/2Iw^2 U_gi=KE_f I=1/2MR^2 The Attempt at a Solution I got as far as far as d then realized that i didn't do anything to include the...
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    Mastering Physics, conceptual problem (no values)

    Thanks guys I got the answer :D a=(g(m_g-mu_km_r)/(m_r+m_g))
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    Mastering Physics, conceptual problem (no values)

    also the acceleration we're looking for is of the first mass.
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    Mastering Physics, conceptual problem (no values)

    Hey everyone, First of all, here is the applet so you can see what the problem looks like. http://session.masteringphysics.com/probhtml/applets/modatt2-14-4a.html I'm supposed to create an equation for acceleration; using m_1, m_2,Mu_k, and g. I'm not sure what the first step is...
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    A skier starts from rest, accelerates down 30degree slope

    Question: those suvat equations, are those used to find the average or instantaneous? What would I use to find inst. velocity vs avg velocity?
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    A skier starts from rest, accelerates down 30degree slope

    I still think each question is separate though i wish the question was more specific.
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    A skier starts from rest, accelerates down 30degree slope

    A question given by my professor, I have an exam in two hours and i procrastinated looking at his review sheet. i emailed him but i doubt he'll get back to me before the time of the test. (i've been studying our past quizzes/hw instead for the past week)
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    A skier starts from rest, accelerates down 30degree slope

    I thought a) and b) and c) where all different questions pertaining to the same problem and unrelated, fml you might be onto something.
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    A skier starts from rest, accelerates down 30degree slope

    I understand that, but velocity is equal to acceleration multiplied by time, but how do I find time? I feel like I am not given enough to solve the problem, i ended up with (t)(4.9m/s^2) as my velocity I don't have the displacement or distance, neither do i have the time. so how can i find the...
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    A skier starts from rest, accelerates down 30degree slope

    For C) For letter C is it simply 750m?
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    A skier starts from rest, accelerates down 30degree slope

    I know its early but can anyone else verify if the work I'm doing is correct? :(
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    A skier starts from rest, accelerates down 30degree slope

    I'm not sure how to find the average velocity. Unless all I have to do is V=at? In which case I get 31.64 m/s
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    A skier starts from rest, accelerates down 30degree slope

    For part b) I used the formula Vf^2-Vi^2=2a(\delta)x For the change in x I found the hypotenuse of the triangle, is that correct? or should I have used the 250m that was given? After plugging in the values I got 63.25 m/s for my instantaneous velocity.
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