Recent content by Puzzedd

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    Graduate Why Does the Binomial Theorem Summation Not Equal 2n When n Varies?

    Thanks! I spent an hour thinking about it last night and couldn't see what I was doing wrong.
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    Graduate Why Does the Binomial Theorem Summation Not Equal 2n When n Varies?

    Using summation((\stackrel{n}{k})xkyn-k) = (x+y)n, I let x = y = 1. This should then result in summation((\stackrel{n}{k})*1*1) = (1 + 1)n = 2n. Expanding the summation, I get (\stackrel{n}{0}) + (\stackrel{n}{1}) + ... +(\stackrel{n}{n}) = 2n. Solving this results in...