Recent content by PVnRT81

The peak velocity is 10.38 m/s.

Homework Statement A shot putter throws her shot. At the moment the 4.00 kg weight leaves her hand, it as a velocity of 14.0 m/s and is 2.00 m above the ground. The weight reaches a maximum height of 6.50 m above the ground before falling back down. What is the magnitude of the weighted...

Ah! That clears it up... however, I am still curious as to why some websites/textbooks choose not to include the mass of the solute.

I would use the mass that is gaining heat - which is the total mass in this case. But in the original scenario, the solute is losing heat, and the solvent is gaining heat... so, wouldn't it make more sense to use the mass of water only because the solute itself is not gaining heat?

Homework Statement Suppose I have a solute of mass "x" grams. I dissolve this in "y" mL of water. The temperature of the water increases by "z" degrees Celsius. I calculate the molar heat of dissolution of the solute by measuring, using q=mwatercΔt, the heat absorbed by water (in kJ), and...

Homework Statement Graphite can be change into diamond according to the following equation: Cgraphite ==> Cdiamond Consider the following reaction equations: Cgraphite + O2 (g) ==> CO2 (g) ΔH = -393.5 kJ/mol Cdiamond + O2 (g) ==> CO2 (g) ΔH = -393.4 kJ/mol Which form of...

Yes, but, according to what PJay has posted, the actual definition of "total work" in this context refers to the net work. But yes, I do agree with you on that point.

So, according to you, part (c) has been correctly calculated? The 12.5 J is the net work that has caused the acceleration of the bucket.

Is part (c) wrong?

The force causes the difference, right?

The excess work aids the student in pulling the bucket up since the gravitational work would remain identical.

If the student pulled harder, there would be more force applied, over the same distance, thus the there would be more work done by the student. If he pulled a little less hard, less work would be done because less force is applied.

The total work can be considered the "net force" x distance. Because this is the actual work that brings the bucket up the well. The difference is because of the two different directions; however, the child pulled with enough force to counteract the gravitational force and thus, pulled the...

My textbook states that if work is being done in an opposite direction from the direction of motion, then it is called resistive work. It's not aiding the movement of the object, rather it is "holding it back".

The gravitational work is resistive, and in the opposite direction.