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Electric field from uniform charge of finite length
Homework Statement A uniform charge Q of length L is placed on the x-axis with one end at the origin as shown a) Find the contribution dE (vector) to the electric field at P on the y-axis a distance y from the origin, from the charge at x in dx, in terms of Q, L, dx, ke, x and y b)...- Pyuruku
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- Charge Electric Electric field Field Finite Length Uniform
- Replies: 1
- Forum: Introductory Physics Homework Help
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Voltage change away from long line of uniform charge
\frac{\lambda}{2\pi\epsilon}\int_{0.05}^{0.1} \! \frac{dr}{r} = \frac{\lambda}{2\pi\epsilon} ( ln(r) \bigr|_{0.05}^{0.1}) = \frac{\lambda}{2\pi\epsilon}ln(\frac{0.1}{0.05}) = \frac{5.0x10^{-6}}{2\pi(8.85x10^{-12})}ln(\frac{0.1}{0.05}) = 6.232 x 10^{4} V (I believe this is now correct)- Pyuruku
- Post #5
- Forum: Introductory Physics Homework Help
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Voltage change away from long line of uniform charge
Would that be E = \frac{\lambda}{2\pi r\epsilon}? If so... \frac{\lambda}{2\pi\epsilon}\int_{0.05}^{0.1} \! \frac{dr}{r} = \frac{\lambda}{2\pi\epsilon} ( ln(r) \bigr|_{0.05}^{0.1}) = \frac{\lambda}{2\pi\epsilon}ln(\frac{0.1}{0.05}) = \frac{5.0}{2\pi(8.85x10^{-12}}ln(\frac{0.1}{0.05}) =...- Pyuruku
- Post #3
- Forum: Introductory Physics Homework Help
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Voltage change away from long line of uniform charge
Homework Statement Find the voltage change going from 5.0cm to 10.0cm along the radius away from a long line of uniform charge density 5.0 μC/m Homework Equations V = (kq) / r (I believe... I'm very lost) The Attempt at a Solution ΔV = ∫.05 to .1 2∏rLdL = 2∏r((L^2) / 2 | from...- Pyuruku
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- Change Charge Line Uniform Voltage
- Replies: 5
- Forum: Introductory Physics Homework Help