Thank you for your suggestions. I realized that I did not mention that x is constrained to be grater than k, this is why I observed a concave-convex function... my mistake.
I could finally prove it. What I did was to look at the first order condition and show that it has a unique solution if...
True in general, and even the third derivative can help, but I do not see how it can be of help here. Please bring your ideas if you have any in this direction.
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I came up with a (sufficient) set of conditions to show q-concavity, but it's rather complex. I put it down in case it helps...
The first derivative of the function is
-\phi(x)(x-k)+(1-\Phi(x))
the first term is always negative, the second always positive, so to prove quasi-concavity is would be sufficient to show that the first term increases in magnitude and the second decreases as x goes up (this would actually...
Homework Statement
I need to prove that the function
(1-\Phi(x))(x-k)
is quasi-concave (i.e. first increasing and then decreasing), where \Phi is the cdf of the normal distribution and k is a positive constantHomework EquationsThe Attempt at a Solution
I plotted the function and even tried...
It is the integral of the pdf of a normal distribution times 1/t. With substitution I get the integral in the title where b is the mean of the distribution. So, if anyone has a solution to compute the integral of (1/t)*PDF(NormalDistribution(mu,sigma),t) from x>0 to +infinity, this would make me...
The reason why I need an analytical solution is that I need to be able to compute the integral in a single Excel cell for any given set of parameter values. So, say that a=20 b=50 and x=80, I need to compute in a single cell (that means without being able to compute partial results in any other...
Homework Statement
I need to calculate the integral of (1/(at+b))e^(-t^2), that is, a negative quadratic exponential divided by a linear function at+b. I need to integrate between some positive x and +infinity.Homework Equations
The Attempt at a Solution
I could find the integral for b=0. In...