Recent content by QuantumForumUser

According to my book on Electroweak Physics, the w1, w2, and w3 bosons form a weak isospin triplet. This probably means the w1 boson has weak isospin -1, the w2 has weak isospin 1, and the w3 has weak isospin 0. Otherwise, the weak isospins of the w1, w2, and w3 could be eigenvalues of the su(2)...

Weak isospin (according to Wikipedia: https://en.wikipedia.org/wiki/Weak_isospin) is a conserved quantity. This means that the weak isospin values don't change whether symmetry breaking happens or not.

What I meant was when the w1 and w2 bosons combine into the w+ and w- bosons through w+ or w- = (w1 -or+ iw2)/sqrt(2). The w+ has weak isospin +1 and the w- has weak isospin -1. So does that mean the weak isospins of the w1 and w2 can be found by rewriting the previously stated transformation...

However, the derivative of a constant is equal to 0.

It appears mostly correct.

When a negative number is under a square root radical sign (√), you can use the multiplication property of square roots (√(ab)=√(a)×√(b)) to change how the answer "looks". Let's say √(-3). The number -3 can factor out as -1 times 3 so √(-3)=√(-1)×√(3). Since i is equal to √(-1), one can write...

I think the nabla symbol ∇ along with σ means derivative of σx with respect to x, derivative of σy with respect to y, and derivative of σz with respect to z.

Do the weak isospins of the w1 and w2 bosons combine as their fields combine?