Recent content by QuantumSpace

  1. Q

    Math From math PhD to space industry - possible?

    Theoretical fluid dynamics does sound like something useful for space industry, but I'm by no means an expert.
  2. Q

    Challenge Math Challenge - November 2021

    My solution for exercise 3. Remark: the same proof works to show that any positive map between ##C^*##-algebras is bounded. That's why I denote the absolute value on ##\mathbb{C}## by ##\|\cdot\|## as well.
  3. Q

    Challenge Math Challenge - August 2021

    Attempt for an elementary solution for (3):
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    Challenge Math Challenge - August 2021

    Also, you can here appeal to the fact that countable union of countable sets is countable, if you are ok with ##|\mathbb{Z}_n[X]| = \aleph_0##. Maybe you are right and I overcomplicate the issue.
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    Challenge Math Challenge - August 2021

    Are you telling me that I cannot use the standard cardinal arithmetic inequalities ##|\bigcup_{i \in I} A_i| \le \sum_{i \in I}|A_i| \le |I| \sup_{i \in I} |A_i|##? Because really that's all I'm using, together with the fact that ##\aleph_0 \aleph_0 = \aleph_0##. Cardinal arithmetic is invented...
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    Challenge Math Challenge - August 2021

    ##|\mathbb{Z}[X]| = \aleph_0## is quite easy to prove. Indeed, ##\mathbb{Z}[X]= \bigcup_{n=0}^\infty \mathbb{Z}_n[X]## so since ##\mathbb{Z}_n[X] \cong \mathbb{Z}^{n+1} \cong \mathbb{N}##, we find $$|\mathbb{Z}[X]| \le \sum_{n=0}^\infty |\mathbb{Z}_n[X]| \le \sum_{n=0}^\infty \aleph_0 =...
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    Challenge Math Challenge - August 2021

    About question (1) I am a little bit confused. Isn't completeness invariant under changing to an equivalent metric? If so, why would you want to change to an equivalent metric?
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    I Munkres Chapter 5: Problem involving the Tychonoff Theorem

    You can use it to give an easy proof of the Banach-Alaoglu theorem, which is absolutely fundamental in abstract functional analysis. And as you said, it can also be used to show that certain compactifications, such as the Stone–Čech compactification, exist.
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