Recent content by quasar7744

Perhaps we need to consider the work of friction even when it is in contact with the spring. But I don't know how to do this part. And no there was no stipulation. I am pretty sure that the velocities are all correct.

the equation I was referring to was 3.386-16.17mu=0.045, when I solve it, I get 0.206, And the correct answer is .2050 to the nearest ten thousandths.

I don't understand how you got 0.212 as the answer, and when I solve that equation, I still get the wrong answer. Thanks

1. A 2 kg object slides down a frictionless track (starting 0.27 m above the ground) to a horizontal surface where it collides elastically with a 0.5 kg mass. 3.3 m later the 0.5 kg mass hits a k=25 N/m spring and compresses is 6 cm. What is the coefficient of friction on the horizontal surface...

When I do it, I now don't get it, i don't know why. I get that t=6.6796482 seconds, so that should make it work. Indeed, that is the correct answer, thanks, problem solved.

Sorry, but I can't see the difference in the equations. you mean -29=-v0*.28+4.9*.28^2, right. But i don't understand why it would be +4.9 and not -4.9. Thanks

Okay, so here is what I have For A, -29=-v0*.28-4.9*.28^2, which implies that v0=102.19994286 m/s For B, -29=-4.9t^2, because it is going horizontally, so t=2.432769481 s. Thus, 12.5=v0*t, because cos0=1, so v0=5.138176921 m/s, for B Then this means that the momentum vector for A is...

1. A 7.1 kg firework is launched straight up and at its maximum height 29 m it explodes into three parts. Part A(1 kg) moves straight down and lands 0.28 seconds after the explosion. Part B(2.5 kg) moves horizontally to the right and lands 12.5 meters from Part A. Part C moves to the left at...