I now tried to incorporate that property and Fubini's theorem
where
DoubleIntegral[ f(x,y)*Delta(y - x*tan(theta)), x,y,-Inf,Inf] = f(0,0) and plugging f(0,0) into Delta(0-0) gives Delta(0,0) which is Infinity. The Fourier Transform of that is 1?
Homework Statement
Given f(x,y) = DeltaFunction(y - x*tan(theta))
a) Plot function.
b) Take Fourier transform.
c) Plot resulting transform.
Homework Equations
Delta function condition non-zero condition DeltaFunction(0) = Infinity
Sifting property of delta functions
The...