Recent content by QuickSkope

Unfortuantetly, I don't have an answer. I'll check it today. Thanks :)

((BA/t)^2 / r) * t gives me (BA)^2 / tR, which is a different equation then the other one I got. So is mine wrong?

I solved L in terms of B, A, R and T, as the question doesn't allow me to use I. Only thing I'm confused about is if I can use V = B * I * L in this situation, as I thought that was for solonoids only.

As shown, I must derive a formula to find work. http://i.imgur.com/0U0eLqm.jpg I proceeded as follows. W= F * D = (B * I * L) * D V = BA/T I = V/R = (BA/t)/R = BA/tR F = B * (BA/tR) * A W = ((B^2*A^2)/tR) * A W = (B^2 * A^3)/tR Does that seem right? IIRC, the B*I*L formula is only...

Yea, I used that method to find the limiting resistor (the first one), then did my method to get the actual value :P Thanks

P=I^2 * r 0.5 = I^2 * 250 I = 0.048 V1 = I * R = 0.048 * 250 = 11.18V V2= (2/3 * i) × R = 2/3 * (0.048) * 300 = 8.944V V3 = (1/3 * i) × R = (1/3) * (0.048) *600 = 8.944V V2 = V3, which is true in parallel. V = V1 + (V2 or V3) V = 11.18 + 8. 94 V = 20.1...

Yea, so I at R1 = I at R2 + I at R3. I'll be back in a bit, but I think I've got it. Answer I got is 11.2 + 8.9, where the first us the first voltage at r1 and the 2nd voltage is the common voltage between r2 and r3. I'll write it out fully when I get home. Also, R1 is the limiting, and I...

So if I do three different one: R1= V/250 R2= V/300 R3 = V/600 2/3 of the current will go through R2, where as 1/3 of the current will go through R3. Beyond that, I'm unsure what you mean.

Ya, parralel sorry. I did my calculation for parralel, so it's all good. For the calculating both together, the Voltage will be the same through both lines, calculating the maximum for each line gives you the maximum for both, and you can't exceed the maximum of one of resistances. Finally...

So if I relate the two currents, the current of the two parallel points must equal the current along the series portion. V= I * R If we leave express I in terms of V, we get I = V/250 And that I must equal the other two Is added together, which is V/600 + V/300 or 3V/600 or V/200 (which is...

Could you have a look at what I've done above? Revamped the post while you were quoting me :).

Using the formula P= v^2/r 0.5 = V^2 / 300 V =12.25 0.5 = V^2 / 600 V = 17.3 Since these two are in series, they will both receive the same voltage. So 12.25 is the maximum Voltage that can be present after the first resistor. 0.5 = V^2 / 250 V= 11.18 So the maximum Voltage that can go...

A system is constructed as illustrated. Each resistor is rated at 0.50 watts. What is the maximum Voltage that can pass through the circuit without burning out a resistor. http://i.imgur.com/uowKVxU.jpg I'm assuming you'd have to narrow it down to which resistor would burn out first, however...

Sweet deal, thanks guys :)

Sweet Deal, thank you guys :)