Recent content by qwertyflatty

  1. Q

    Shouldn't objects entering black holes be instantly shredded?

    I'm not talking about tidal forces, and I'm not talking about hovering near an event horizon. When an object enters the event horizon, the entire object can't enter at the same instant. The same is true for a person passing through any point. Ex. A person diving into a swimming pool would...
  2. Q

    Shouldn't objects entering black holes be instantly shredded?

    I'm not talking about tidal forces. Anything that crosses the event horizon can't get out. When an object crosses the event horizon, it doesn't all cross at the exact same time. Only parts of it cross at any instant. If nothing inside the event horizon can get out, then the atoms of the...
  3. Q

    Shouldn't objects entering black holes be instantly shredded?

    I mean instantly, as it's entering the event horizon. Spaghettification may happen sometime after passing through the event horizon.
  4. Q

    Shouldn't objects entering black holes be instantly shredded?

    Nothing can escape a black hole, so as an object enters the event horizon, the atoms currently inside the black hole wouldn't be able to bond with the atoms currently outside of the black hole, causing it to sever. But I've never heard of any physicist saying that this would happen, so I'm...
  5. Q

    Equivalent Resistance in Diamond-Shaped Circuits

    Hmm, so there's no way to simplify the circuit into one resistor unless R1/R4 = R2/R3?
  6. Q

    Equivalent Resistance in Diamond-Shaped Circuits

    No, your circuit looks like this: | /|\ \|/ | My circuit looks like what the person above just posted. I created the circuit using a circuit simulator, and it showed that there would be no current flowing through the middle resistor...
  7. Q

    Equivalent Resistance in Diamond-Shaped Circuits

    How would I find the equivalent resistance of a diamond-shaped circuit? Is the middle resistor simply omitted? By diamond-shaped, I mean it looks like a Wheatstone bridge, but it has a resistor in the middle instead of a current detector.
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