It is for long term use. Actually, it is a cell phone battery. even if I am able to charge 10% of the battery I am fine. I am looking for something like say crank for 3 minutes and talk for 5 minutes or more. Will it be possible??
Ok, now I have decided to use a different charger.
5 VOLTS and 1000 Milli Amp and cells as well say 3.7 V and 1500 MAmp.
how do you calculate how much time a charger will take to charge a battery? and how much cranking is needed for same.
Secondly, if the cells accept 3.5 volts then how a...
I checked it. It is a 5 Volt and 350 mAmp charger. Now, how do I find a dynamo which can charge it and how much time I would have to crank in order to charge it fully?
Please help..
Hello
I am working on a project to charge a small battery say of 3.5 Volts and 1000 Milli Amp through cranking/wind up but I am not able to figure out what dynamo is required and how much time I would have to crank in order to draw the required power(3.5 Watts) in order to charge the battery...
So, now for both the clocks the other one is slow. What will happen in case these both clocks meet each other. Imagine the clocks reverse their path to meet each other.
hmmm... so you want to say that time is not some universal duration its just the duration between two successive events. For each of the moving observers the successive events occur slowly at the other one.
But for your question each clock measures one second correctly for its own observer but...
But in the light clock article, when the observer is moving the light should have traveled at c+speed of observer but according to STR its speed remains constant and hence dilation occurs. Thus basic velocity addition fails at speed of light.
Time delation or clock malfunction!
Using an example of light clock, it shows light takes more time now to reflect between reflectors due to elongated path as to moving observer, so 1 sec gets elongated. But this could also mean that the clock malfunctions as compared to observer. I mean one...
Whether the clock is moving or the observer, its one hand same thing for the observer. I prefer taking observer to be mobile because if clock is moving (say at very high speed) then photon will not move along with clock and at some instance it will miss one of the reflectors. Moreover, the speed...
The clock was relatively moving for the observer(for he himself was moving) and the photon in the clock which was traveling at speed c must now be moving with [ c+observer or clock speed] but that is not possible, so it travels with c. That means the photon in moving clock (to the observer)...
In case of light clock even, when observer travels at some speed, path of photon appears elongated to the moving observer now the velocity of observer should have been added to velocity of light which we know is not possible so the overall velocity of photon for the observer is constant i.e c...
Then what causes the differential aging? How does STR solves the paradox. This may be very elementary question but I don't have solid understanding of relativity. Can you explain how STR solves paradox or can you give me good references where I can get my answer?
If so, then STR can't solve twin paradox? bcoz all the articles on internet say that it is acceleration which causes the the traveling twin to age less than the one who stayed on earth.
If acceleration is necessary for differential aging, how can twin's paradox be solved without involving general relativity? i.e solely on the basis of STR.