Recent content by radicaled

Ok, I have attached the circuit. As for the problem statement its the same. I may rephrase, because I have to translate it - Obtain the impedance - The effective current without inductive coupling

We consider the B into the page

Sorry i think I forgot to add that. The direction of the current I took was clockwise. The magnetic field, comes from the exercise description, is perpendicular to the plane of the circuit.

The exercise goes like this: - Obtain the impedance - Current effective without inductive coupling Data: v(t) = 100 sin(1000t + π/3) R = 1kΩ L1 = L2 = 1H C= 1μC Resolution: Z = \sqrt{R^2 + (Xl - Xc)^2} Z = \sqrt{1000^2 + (1000.2 - \frac{1}{1000 1x10^{-6}})^2} Z = 1414,21Ω...

Ok, so I did this: For the semi circumference F = I \bar{I}x\bar{B} in the -j direction So F = 5A \pi0.1m 3.4x10^{-3}T = 5.3x10^{-3}N Now for the sides of the rectangle: F = I \bar{I}x\bar{B} in the -i and in +i direction. So they cancel each other? F = 5A 0.1m 3.4x10^{-3}T =...

Homework Statement the current is i, the circuit is in a uniform magnetic field B normal to the plane of the circuit as indicated Attached is the circuit Homework Equations Get the forces acting on each of their sides. Direction and data module for the following: L = 10cm R = 10cm I =...

Ok, but if I want to calculate the maximum current I'm going to need the v(t)=Ri(t) + L \frac{di}{dt} + \frac{1}{C}\int idt ecuation, and I'm stuck there. Otherwise, there is any other way to obtain the max current with the data I have?

I guess you could. I'be been thinking this exercise a couple of hours and I miss it. But you can use the sinusoidal variables with the rest? Z=V/I

The problem The exercise goes like this: A sinusoidal source v(t) = 40 sin(100t) its applied to a circuit RLC with L=160 mH, C=99 μF and R=68Ω. Calculate a) the impedance of the circuit b) the maximum current My solution a) If v(t) = 40 sin(100t) --> ω=100Hz Z= \sqrt{R^{2} +...