Recent content by raizen91

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    More projectile motion problems (sigh)

    ok, here's what i did. v[sub]x = r / t d[sub]x/ v[subx] = v[sub]x * t / v[sub]x = 1931,216.66 m / 4572.009 = 422.4 seconds now for the angle cos[theta] = v[sub]x / v[sub]x = 4572.009 / 4572.009 =1 = 60 degrees ok...is this right?
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    ok, here's what i did. v[sub]x = r / t d[sub]x/ v[subx] = v[sub]x * t / v[sub]x = 1931,216.66 m / 4572.009 = 422.4 seconds now for the angle cos[theta] = v[sub]x / v[sub]x = 4572.009 / 4572.009 =1 = 60 degrees ok...is this right?
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    err... :confused: thanks for the help but I am really confused, can you walk me through your solution. you're right, I've been provided with other solutions but they only made me more confused. id like to stick to how you do it. can you to start from the top? and can you explain using simple...
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    ok, what is did was to first convert ft and miles to meters. using the formula you gave v(sub)x = v(sub)o cos (thetha) 1931212.8(1200 miles) = 4572cos(theta) then for y 0 = 4572sin(theta)*t - 4.9[sup]2 err..ok. am i at the right path?
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    More projectile motion problems (sigh)

    got two more problems, hope you could help. more projectile problems...(sigh), i don't know how to start, hoping you guys could help me with the initial steps... 1. a missile is fired with a launch velocity of 15,000 ft/s at a target 1,200 miles away. at what angle must it be fired to hit...
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    i got two more problems, hope you could help. more projectile problems...(sigh), i don't know how to start, hoping you guys could help me with the initial steps...1. a missile is fired with a launch velocity of 15,000 ft/s at a target 1,200 miles away. at what angle must it be fired to hit the...
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    will the answer be 19.6? i don't know about ur formula but i have used a different approach. since the the time is 4 sec., i would assume that the ball will reach its highest point at 2 sec. so i used two formulas which is v^2 = v[sub]0^2+ 2as and v = v[sub]0 + at so 0 = v[sub]o +...
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    Projectile motion - no angle given?

    projectile motion - no angle given? how do i solve for a problem if no angle is given? only time and range is given.
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    yap I am ten..but I am in my 5th grade. i find it quite silly when our teacher thinks that we're smart enough to answer questions as difficult as this..
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    sorry...that's all the info our teacher gave us. my classmates and i had the same prob... like no angle?
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    Solving a Projectile Motion Problem: Maximum Height of a Batted Baseball

    hello guys! i find physics really difficult and my classmates and i have been dumbfounded by this problem. hope you could help me with the formulas i should use and how is should use them. this is was the first problem: ooops..this problem aint a trajectory problem. its a projectile motion...
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