the calculation yungman gave is perfectly fine, but i have a capacitor also in the line in excess, i need to include it, which is 0.01μf which helps to block the dc supply from other side. and also is it possible to increase the value of inductor because the 1.5nH will be available only as SMD...
the main reason, i can't jump with yungmans result is because, i have designed a PCB with true hole components and hence the value of inductor is too low. i can get only SMD inductors, which can't be fixed over it. so is the any other way to design the high value of inductor or neglect it and...
the frequency is fixed to 2.6GHz and not varied. i got confused with the q value due to a web link, please clarify this to me.
http://www.raltron.com/cust/tools/network_impedance_matching.asp
it states q = frequency / bandwidth.
as i have searched many places, the value of Q value is Frequency / Bandwidth. hence my frequency is 2.6GHz and bandwidth is 20MHz. then the Q value is to be 130. Is this is the way to find out the value of Q or is the above value shown by yungman. The actual design is shown below, the capacitor...
this is just a very small part of my project ... still i have to do a lot of work in this project... i have already characterised the laser, but there was a loss in output . that is the main reason i was looking into this impedance matching... i totally have 3 months yet to go... within that i...
could you please show me the maths calculation for impedance matching for the idea you gave as connecting L in series and C in parallel or vise versa. i am really sorry that i could not sent the pcb to you, because this project a very big one, which is used by a research guy too...
the input impedance value is 50Ω and the output or load is 25Ω typically . so how to match impedance between those two resistor value and the important thing is , use only capacitor and inductor in the circuit. the input signal is RF signal and the output is a laser diode.
i have designed my circuit, but i am confused about impedance matching. i know we can use a resistor for matching, but is it possible to use a capacitor or inductor for matching the impedance in a circuit.