Recent content by ramalik

ohhh I see, I got it right! Thank you for your help!

I'm still not getting this problem. I found the force of the diagonal and since the angle it makes is 45 degrees, I found the x and y components of this force. Then I found the force on 1 in the Y direction and since the charges are +, +, -, - in the clockwise direction, there are no other...

Aren't the other two the components of the diagonal force? I found the diagonal force using the pythagorean theorem so isn't that the same thing?

i thought you have to use the absolute value of the charge so that the sign doesn't matter

and i did make sure to convert from microcoulombs to coulombs

For Fx and Fy I used the formula F = (k qq)/r^2 and used the data given. For Fdiagonal, I found the radius of the square which was sq root of( .29^2 + .29^2) and used the same formula. Then I added the three together. I know that's not right because the three forces aren't positive I just don't...

Oh sorry! I tried adding the 3 forces acting on each charge, so its Fx + Fy + Fdiagonal. I am just confused about what to do with the signs since the way I'm doing it does not incorporate them but I know I have to since the direction of the force is important in determining the net force acting...

There are four charges, each with a magnitude of 2.5 microcoulombs. Two are positive and two are negative. The charges are fixed to the corners of a 0.29-m square, one to a corner, in such a way that the net force on any charge is directed toward the center of the square. Find the magnitude of...

An irregularly shaped chunk of concrete has a hollow spherical cavity inside. The mass of the chunk is 38 kg, and the volume enclosed by the outside surface of the chunk is 0.025 m3. What is the radius of the spherical cavity? I think you have to find the surface area to solve for the radius...

2.6-1.1 = 1.5 m. Thanks!

the center! so i have to find the difference between the center point and the piece hanging off the side?

A uniform plank of length 5.2 m and weight 213 N rests horizontally on two supports, with 1.1 m of the plank hanging over the right support (see the drawing). To what distance x can a person who weighs 445 N walk on the overhanging part of the plank before it just begins to tip? I know you...