Recent content by ramble

I see... thx~ Too much used to real no... have never thought that there would be a problem on that line (never thought of posting a question in a forum could get immediate response too~ ^^)

Sorry forgoth I haven't noticed your reply when i post mine... but I do not understand... do you mean that I cannot square a complex no?

according to my proof, instead of \mid z + \overline{z} \mid \leq 2 \mid z \mid, it is \mid z + \overline{z} \mid \geq 2 \mid z \mid... z is a complex no. and \overline{z} is its conjugate. Have I mixed up some basic rules in complex no. with those in real no.?

I would like to prove \mid z + \overline{z} \mid \leq 2 \mid z \mid The first way I could think of: \begin{multline} RHS^2 - LHS^2\\ =4\mid z \mid^2 - \mid z + \overline{z} \mid ^ 2\\ =4z\overline{z} - (z + \overline{z})(\overline{z}+z)\\ =4z\overline{z} -...