Hehe... nice point of view! :rofl:
However, this, being an exam problem, is assumed to be a little bit more complicated than simple arithmetics. :rolleyes:
I think it is enough to know the radius, the angular velocity (or frequency) and the time to read one bit (or distance b/n bits)... Once...
OK, if the question asks about how many megabits are read in one revolution, you say that "it should be pretty easy". Still, it is very foggy for me :-). Perhaps you could provide a small tip? ;)
Hi, guys! :approve:
My exam comes in one week, so I need your urgent help :cry:
I found out, that one of the problems in the exam will be about convertion between rounds per minute (of a CD or HDD) and megabits per second (as reading speed). I have no idea what is the dependence between...
I just found out some clues and answers:
For (c): if it is vibrating in its fourth harmonic, the length is L=2\lambda=62,8.
For (b): The dist. between successive nodes is just half of the wavelength -> 15,7.
Does this mean that I answered myself? :biggrin: Where are you, guys?? Anybody home...
Hi again :biggrin:
The first part of my question was stated under "Simple math problem". However, the rest subproblems are no more simple math ones only :rolleyes:
I'm given the wave function y(x,t)=4.2\cos(0.2x)\sin(300t).
(a) What are the speed and amplitude of the two traveling waves...
Thank you guys, you really helped me! :smile: It seems that I've got the point now...
However, I have one or two more questions about this problem (I've not stated them yet), but I think I will post them in a new thread, because they are not "simple math problems" any more :rolleyes:
So for...
Following the advices of you both, I calculated the values for x when the cos is 0: x=\frac{\pi}{0.4} and x=\frac{5\pi}{0.4}, so the distance between two successive knots is 10\pi. This gives me the wavelength \lambda. :tongue2:
The period for one full cycle I obtained in the same way, using...
OK, If I take in mind that wavelength is the distance between successive points of equal amplitude and phase on a wave, and frequency is the number of cycles or events per unit time, I take the given equation y(x,t)=4.2\cos(0.2x)\sin(300t) and I see that it has a double frequency (due to...
I suppose first principles means straight from the given equation, without transforming it in any way. :shy:
However, being new to this field, makes it a little more difficult for me to understand such hints. Probably if you provide a little more specific tips or advices, I will be able to...
That's right and exactly this confuses me :rolleyes:. But leaving the confusion aside, I obtain from y(x,t)=4.2\cos(0.2t)\sin(300t) the function y(x,t)=2.1(\sin(300t + 0.2t) + \sin(300t - 0.2t)). So if \lambda=\frac{2\pi}{k} and I leave the sign, I get \lambda=10\pi. For...
The problem is that I don't know how to deal with such separated expressions - one for sin (containing "t") and one for cos (containing "x")... If it is a superposition, then how to separate the two functions?!
Simple wave problem
Hi guys!
I'm trying to solve a wave problem for homework and I hope that I can extract all data, once I have my wave function in the form: y(x,t)=A*sin(kx-wt) :biggrin: . The simple problem is to convert the given data: y(x,t)=4.2*cos(0.2x)*sin(300t) into the above form...
HallsofIvy, I forgot to mention that my teacher even provided a picture with a man, who is standing on that spring and lifts weights :biggrin: ... for those of us, who can't imagine :tongue2: . That creates the imagination of an object with a very big mass! But whatever...
I just want to ask...