OK, so this is a "Wheatstone Bridge". The more you know...
Now since C1/C5=C4/C3 the voltage at points 1 and 2 (both sides of C2) is equivalent, thus there is not current flowing through C2 and I can just ignore it. Then I end up with C1 and C5 on one side (1/Ceq_a=1/C1+1/C5) and C4 and C3 on...
I'm having a time figuring out how to solve this one, hope someone can help me out
Homework Statement
"Calculate the equivalent capacitance between X and Y on the circuit in the figure. C1=C3=C4=C5=8uF, C2=20uF"
Homework Equations
The Attempt at a Solution
I can't figure out a...