Well using the Henderson-Hasselbalch equation,
6.8 = 4.75 + log [CH3COOH]/[CH3COONa];
log [CH3COOH]/[CH3COONa] =2.05
After which, I approach a problem!
Hello!,
I have encountered a problem relating to buffer solutions. The question states that I am to make a Sodium Acetate buffer solution of 0.25mol l-1, at pH 6.8. The reagents used to make the buffer solution however, is Acetic acid and Sodium Hydroxide. The pKa of Acetic acid is given as...