Recent content by rashida564

Let's say we have two people that travel with respect to each, other in some inertial frame. So if we took the relative velocity of them will they be the same in as v^12+v2^2

I think since Esystem=(PsystemC)^2 + (Minvariant C^2)^2. Then the invariant mass of the system should be zero, but I am hesitated with this is it always the case that photon that travels perpendicular to each other have zero invariant mass

Is it try and error method?

Hi everyone, I can find multiple of number for example 2,3,4 and so on. But is there any reason why those number does work.

It's to the center and equal to v^2/r

w must be equal to v, but I don't know how to define w. like what's it's formula

Yes sir sorry for my messy writing, this what I am trying to figure out, the left hand side is " |d→Adt||dA→dt| clearly g, the ##|\vec A|\## is v, but I don't get what's w

that's from the rotation of axis. Like any vector. dA/dt= A*w. where w is the rate in which it changes it's direction. Not sure why this vector change it's direction by magnitude of v

Is it true this way because it will be a rotating vector, or I just got it by pure luck again😭😭😭 not sure though why should it v times v

The direction of the acceleration. It must be tangential to the curve

can you give me a hit of what should I do

I got the correct answer which is √g. I solved it as if it were a circular motion with radius of 1. But got no idea why my solution did work.

I am confused why the acceleration doesn't point to the center of the ellipse or one of the focus, since it moves in circular motion. Shouldn't the acceleration be just in the radial direction

Thanks mate, now I see my mistake.

I am thinking about solving it this way. The first three equation is from Newton law. Then the forth one is the constrain equation, after that I simplified the first three equations, and I am thinking about plugging them into the forth equation and solve for T after that I get the value of...