continue
OK, i got the answer for y(n)=x(a*n), where a is an integer. Y(e^j\omega) can be defined.
it is (1/a)*\sumX(exp(j(\omega+2\pim)/a)) where m varies from 0 to a-1.
But can anybody please tell; is it possible for y(n)=x(n/a) to define Y(e^j\omega). i am getting confused becoz of 0's...
I wanted to know , if x(n) has DTFT X(e^jw)
then can we define Y(e^jw) in terms of X(e^jw)?
where Y(e^jw)is DTFT of y(n)=x(a*n)or y(n)=x(n/a). Because in these cases terms of x(n) are either missed or '0' is padded up, so i think it won't be possible to define Y(e^jw) in terms of X(e^jw)...
High pass filters are those circuits which allow higher frequency component of any i/p signal to pass & blocks lower frequency. And just opposite for Low pass filter. See the attachment. in low freq section gain is low and it increases with frequency. Thus allowing higher frequencies in that...
Frequency analysis of transistor amplifier shows behavior of amplifier at different frequency. Like at low frequency effect of coupling & bypass capacitor becomes significant. So gain of amplifier changes with freq. In this region of frequency amplifier acts as High pass filter
At high...
Sorry made mistake
Sorry made a mistake there it should have been
if i/p is x1(t) , then
o/p is y1(t)=Cx1(t)+k
if i/p is x2(t) it becomes
y2(t)=Cx2(t)+k
now to obey linearity if i/p is a1*x(t)+a2*x(t), then o/p should be
y(t)=a1*y1(t)+a2*y2(t)
but in this case if i/p is...
look if i/p x(t) is scaled by a1, then
o/p is y1(t)=a1*Cx(t)+k
if scaled by a2 it becomes
y2(t)=a2*Cx(t)+k
now to obey linearity if i/p is a1*x(t)+a2*x(t), then o/p should be
y(t)=y1(t)+y2(t)
but in this case if i/p is a1*x(t)+a2*x(t)
y(t)=a1*Cx(t)+a2*Cx(t)+k
which is not equal...
Some teacher told me this If we have hollow sphere (of conducting material) with some thickness. and if we place a +ve charge inside that . -ve charge induces on inner surfuce, Which further causes in outer sphere & that becomes positivly charged. is this right? Please give right explanation.
Observation for such case should be done from an inertial frame. Since B returns (thus accelerats & it is only felt by B). its frame reference can't be selected. So u can choose A's reference Or any other inertial frame. U'll find that twin who returns, is younger.
2nd postulate of SR says that speed of light is constant in all inertial frames. And it exlains all SR. but How to prove this? I have seen that michelson-morley experiment can be explained by this. Is this exp is only reason?:confused: