Recent content by Ravi Ramdoolar

this was given Mass of Felix = 70 kg Gravity = 9.8ms^-2 Air resistance proportional constant K = 110 kgs^-1 terminal velocity without parachute, v1 = 52ms^-1 Terminal velocity with parachute v2 = 6.2ms^-1 what do i do from here ??

this is what i did so far ma = mg - kv (since kv is the opposite direction as the gravitational force) md2x/dt2 = mg - k dx/dt

yes when the parachute opens it is Kv and before it is Kv2 i am mostly sure we have o use the Kv since the question asked when the parachute was open

ok will try something:approve:

i don't know i think the gravity will be the acceleration:confused:

This is what i did

F=ma kv=md2x/dt2 kdx/dt=md2x/dt2 from here i don't know where to go i don't even know if this is correct does anyone know how to work it out ?

Homework Statement Felix, a Red bull skydiver, (mass m) who drops out of a hovering helicopter, falls long enough without a parachute(so the drag force has strenght kv2 ) to reach his first terminal velocity ( denoted v1). When his parachute opens, the air resistance force has a strenght Kv...

an the initial temperature was 27°C of the water beforeheat was applied

just please take the ice as 0°C

the cup is made out of styro foam an it was an experiment an that was the results

Homework Statement mass of cup 1.78g initial mass of water and cup - 54.26g finlal mass of water after ice added - 91.26g initial temperature - 27°C temperature after heated - 92°C temperature after ice added - 35°C problem 1) how much heat energy did the original mass of water lose...