Calculating Heat Energy Changes in a Water and Ice System

Click For Summary

Homework Help Overview

The discussion revolves around calculating heat energy changes in a system involving water and ice. The original poster presents a problem that includes various measurements related to mass and temperature, seeking to determine heat energy lost by water, energy gained by melted ice, and energy required to melt the ice.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations attempted by the original poster, questioning the sources of the numbers used in the calculations. There is a focus on ensuring clarity in the problem setup, particularly regarding the state of the ice and the relevance of initial temperatures.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem's parameters and the original poster's reasoning. Some guidance has been offered regarding the importance of showing work in symbolic form before substituting numerical values.

Contextual Notes

There is mention of missing information, such as the material of the cup and the initial state of the ice. Participants are also exploring the implications of assuming the ice is at 0°C.

Ravi Ramdoolar
Messages
12
Reaction score
0

Homework Statement


mass of cup 1.78g
initial mass of water and cup - 54.26g
finlal mass of water after ice added - 91.26g
initial temperature - 27°C
temperature after heated - 92°C
temperature after ice added - 35°C

problem
1) how much heat energy did the original mass of water lose?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
3)calculate the amount of heat energy required to melt the ice

Homework Equations



Q = mcΔθ
Q = mLv

The Attempt at a Solution



1) Q= .093 × 4200×57 = 22264 J

I am not sure if this is correct i don't know what to do for the other two including this one could someone help me please :confused:
 
Physics news on Phys.org
Ravi Ramdoolar said:

Homework Statement


mass of cup 1.78g
initial mass of water and cup - 54.26g
finlal mass of water after ice added - 91.26g
initial temperature - 27°C
temperature after heated - 92°C
temperature after ice added - 35°C

problem
1) how much heat energy did the original mass of water lose?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
3)calculate the amount of heat energy required to melt the ice

Homework Equations



Q = mcΔθ
Q = mLv

The Attempt at a Solution



1) Q= .093 × 4200×57 = 22264 J

I am not sure if this is correct i don't know what to do for the other two including this one could someone help me please :confused:
Welcome to PF Ravi.

First you should give us the complete problem as written. There is some information missing here. What is the cup made of? Second, you must explain your reasoning and tell us where you get these numbers.

AM
 
Andrew Mason said:
Welcome to PF Ravi.

First you should give us the complete problem as written. There is some information missing here. What is the cup made of? Second, you must explain your reasoning and tell us where you get these numbers

AM

the cup is made out of styro foam an it was an experiment an that was the results
 
Ravi Ramdoolar said:
initial temperature - 27°C
How is that relevant?
2) what is the gain in the energy of the melted ice as its temperature rose from 0°C
Are you sure the ice was at 0C?
1) Q= .093 × 4200×57 = 22264 J
It's not at all clear where you are getting those numbers from. It's much better to do the working in symbols, only plugging in numbers at the end. At the least, please show how each of those numbers comes from your raw data.
 
haruspex said:
How is that relevant?

Are you sure the ice was at 0C?

It's not at all clear where you are getting those numbers from. It's much better to do the working in symbols, only plugging in numbers at the end. At the least, please show how each of those numbers comes from your raw data.
just please take the ice as 0°C
 
Ravi Ramdoolar said:
just please take the ice as 0°C

an the initial temperature was 27°C of the water beforeheat was applied
 
Ravi Ramdoolar said:
an the initial temperature was 27°C of the water beforeheat was applied
Yes, I understand that, but I don't see how it is relevant to the questions. They all seem to concern what happened after the water had been heated.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K