Recent content by rc2008

Ok, understand that both curves must be differ by 90 degree to make the ##\(A^2)+(B^2)## work. In this case, simply sum up the curves of function having different frequency would be the upper limit ?

Thanks, I do not have suffcient knowldege on mathematics. For this kind of superpostion of curve, is there any shortcut formula to find the amplitude of superimposed curve other than more comprehensive analysis like Matlab?

Thanks for the info, this is related to dynamics courses and not mathematics courses. So , the approx value shall be good enought. I am struggling to find out the max amplitude of superposition of forces of different function and different frequency. For the ##\sqrt {A^2+B^2}## rule , does it...

Thanks, looks like I can only use pythagora's theorem for cos and sin curve with same frequency. for superposition of sin + sin / cos+ cos / sin+cos curve with different frequqncy, i can only just simply add up to get the magnitude of superimposed curve, correct me if I am wrong...

My reasoining is superimpose the Asin and Bcos curve having the same frequqncy first, then I would get resultant curve of ## \sqrt(A^2+B^2)## ## \sin(θ+φ)##, then I only superimpose the resultant curve with other cos curve and sin cruve having different frequnecy, correct me if I am wrong.

My answer is ## \sqrt((300^2)+300^2)## = 424 after superimposing both ##cos13πt## and ##sin13πt##, After which, the overall of amplitude of superimposed of all 4 forces are ##\sqrt( (434^2)+ (500^2) + (600^2))## = 893, correct me if I am wrong

## BC1: At x=0x = 0x=0, v=0v = 0v=0: c2+θBL=0c_2 + \frac{\theta_B}{L} = 0c2+LθB=0• BC2: At x=Lx = Lx=L, v=0v = 0v=0: c1sin⁡(ωL)+c2cos⁡(ωL)+VEIL+θBL=0c_1 \sin(\omega L) + c_2 \cos(\omega L) + \frac{V}{EI} L + \frac{\theta_B}{L} = 0c1sin(ωL)+c2cos(ωL)+EIVL+LθB=0• BC3: At x=0x = 0x=0, v′=θBv'...

Taking B as origin, the boundary condition provided was ##v(x=0)= 0 , v(x=L)=0 , v'(x=0)= \theta B## ##v'(x=L)=0## , and also ##v'' (x=0) = M_B/ EI## However, I had problem of expressing the equation in terms of ## \omega L## Can anyone help ?

For ##\cos x+\sin (2x)\ ##, I would also get 2, simply because of shape of ##\cos (x) \## will coincide after some time. For my case of 4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)## , I am not sure whether they will coincide or not because 10 is not a whole numer of multiplier of 5.4

For ##\cos x+\sin x\ ##, i would get 2 , simply because ##sqrt(1+1)## = 2

My answer is simply 4.6+ 3.2 = 7.8m , correct me if I am wrong. If it's 4.6 ##\cos(2\pi*5.4x)## and 3.2 ##\sin(2\pi*10x)##, then the max amplitude should be sqrt(4.6^2 + 3.2^2) = 5.6m, correct me if I am wrong.