Recent content by rectifryer

How can I determine concavity if y'' has no real solutions?

The function's domain is [-1,-1/2)U(-1/2,1] VA @ x=-1/2 HA @ y=+-1 Correct? Also, Those two derivatives are y' and y''. My apologies, thanks for correcting. The function intersects the y-axis at (0,1).

Homework Statement Y=\frac{\sqrt{1-x^2}}{(2x+1)} Homework Equations I took the first derivative which I believe to be: \frac{(-x-2)}{(2x+1)^2\sqrt{1-x^2}} I also took the third which I believe to be: \frac{4x^3+12^2-7}{(2x+1)^3(1-x^2)^(3/2)} I am trying to find zeros of the...

I have narrowed down my question, specifically to the area I have highlighted on this picture (bear in mind, I can't post pics under 10 posts): http:// i.imgur .com /62erw.png Where did all the dx/dt and dy/dt come from on the right side? I don't understand that step. I know how to...

That doesn't really seem like it would get me anywhere. I know I am wrong, but why would that work? Thank you for the links.

Homework Statement s=\sqrt{(3x^2)+(6y^2)} Homework Equations None The Attempt at a Solution \stackrel{ds}{dt}=\stackrel{d}{dt}\sqrt{(3x^2)+(6y^2)} \stackrel{3x}{\sqrt{(3x^2)+(6y^2)}} The problem with that is its only d/dx if y is a set number. I don't know how to...

Incredible. Thanks a lot everyone!

Thanks for writing that out in latex. I have bookmarked your sig haha. I will email my teacher. We are doing problems in MathXL and there seems to be some disconnects from what it asks and what the teacher appears to have asked.

If I use L'Hopital's rule then it comes out with the right answer, however, my teacher hasn't covered this rule and I don't think we are supposed to use it.

Homework Statement Lim (cosθ-√3/2)/(θ-pi/6) θ→pi/6 Homework Equations The Attempt at a Solution My attempt at this has been to try to multiply both the numerator and denominator by either the numerator's or denominator's conjugate. both result in 0 at the denominator. I also...