Recent content by ReginaldN
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Squeeze Theorem with limits n/n as n approaches 0
that must be true, because no matter what integer n is, it will always end up as 1/n. For example, if n = 2 , then the equation would be 2/22, which is 21 / 22, and that would equal 1/21.- ReginaldN
- Post #11
- Forum: Calculus and Beyond Homework Help
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Squeeze Theorem with limits n/n as n approaches 0
So for about half of the values of n, half of them will be great than or equal to 1/2, right?- ReginaldN
- Post #8
- Forum: Calculus and Beyond Homework Help
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Squeeze Theorem with limits n/n as n approaches 0
okay so, for n=6. everything less than 3/6 is less than or equeal to one half? I'm not really understanding what you mean by generalize.- ReginaldN
- Post #6
- Forum: Calculus and Beyond Homework Help
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Squeeze Theorem with limits n/n as n approaches 0
hmm, isn't 2/2^2 equal to 1/2? So only one of those is less than or equal to 1/2?- ReginaldN
- Post #4
- Forum: Calculus and Beyond Homework Help
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Squeeze Theorem with limits n/n as n approaches 0
Isn't it just n^1? Which is just n?- ReginaldN
- Post #2
- Forum: Calculus and Beyond Homework Help
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Squeeze Theorem with limits n/n as n approaches 0
Homework Statement The question asks to use the squeeze theorem to show that the limit of n!/n^n equals 0 as n approaches ∞. Homework Equations I need to use the squeeze theorem to solve this problem, and I'm not sure what the upper limit is. The Attempt at a Solution I found...- ReginaldN
- Thread
- Limits Theorem
- Replies: 10
- Forum: Calculus and Beyond Homework Help