So from that, we get.FBD=100cosθi + 100sinθj
The system is in equilibrium so FBD=FBA+ FBC
FBA=-mgj
FBC= FBCsin22.62i - FBCcos22.62j
Would I be correct in assuming that the magnitude of the force on BA and BC add to 100 lb?
If so, where would I go from there?
Homework Statement
The cords ABC and BD can each support a maximum load of 100 lb. Determine the weight of the crate, and the angle θ for equilibrium.
Homework Equations
∑F= 0
∑Fx=0
ΣFy=0
Setting derivative of an expression to zero To find critical point
Second derivative test for determining...
I used 4cos(2x)+4 for the height so A=4sin2x(4+4cos2x). I derived that and still got 30 for the angle. Substituting that into the Area formula, I get 12(sqrt(3)) which is the same as the answer I got when I solved in terms of h
So A= 1/2 (4cos(2θ))(4sin(2θ))
= 8cos(2θ)sin(2θ)
deriving this, we get A'= -16(sin(2θ))2 + 16(cos(2θ))2
setting it to zero, we get θ= 30 degrees
substituting this for θ we get 2(sqrt(3))
However, another part of the question was solving the area in terms of h (I used A=...
That would be sine. So if I were to use that, I would get sin(2θ)= [sqrt(16-(h^2))]/4. But I don't understand what this would accomplish since we're trying to look for max area, and that involves base and height