Recent content by reigner617

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    Determine maximum weight and angle for equilibrium

    But how do we calculate the weight of the crate?
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    Determine maximum weight and angle for equilibrium

    So from that, we get.FBD=100cosθi + 100sinθj The system is in equilibrium so FBD=FBA+ FBC FBA=-mgj FBC= FBCsin22.62i - FBCcos22.62j Would I be correct in assuming that the magnitude of the force on BA and BC add to 100 lb? If so, where would I go from there?
  3. R

    Determine maximum weight and angle for equilibrium

    If we are to take that approach, then would the crate have to be 100 lb?
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    Determine maximum weight and angle for equilibrium

    Homework Statement The cords ABC and BD can each support a maximum load of 100 lb. Determine the weight of the crate, and the angle θ for equilibrium. Homework Equations ∑F= 0 ∑Fx=0 ΣFy=0 Setting derivative of an expression to zero To find critical point Second derivative test for determining...
  5. R

    Optimization of the Area of a Triangle

    I used 4cos(2x)+4 for the height so A=4sin2x(4+4cos2x). I derived that and still got 30 for the angle. Substituting that into the Area formula, I get 12(sqrt(3)) which is the same as the answer I got when I solved in terms of h
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    Optimization of the Area of a Triangle

    Ah thank you for pointing that out. It works now. The 1/2 was put there by mistake because I was thinking fo 1/2 (bh). Thank you for all your help
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    Optimization of the Area of a Triangle

    So A= 1/2 (4cos(2θ))(4sin(2θ)) = 8cos(2θ)sin(2θ) deriving this, we get A'= -16(sin(2θ))2 + 16(cos(2θ))2 setting it to zero, we get θ= 30 degrees substituting this for θ we get 2(sqrt(3)) However, another part of the question was solving the area in terms of h (I used A=...
  8. R

    Optimization of the Area of a Triangle

    Ahhh never mind. I think I see it now
  9. R

    Optimization of the Area of a Triangle

    That would be sine. So if I were to use that, I would get sin(2θ)= [sqrt(16-(h^2))]/4. But I don't understand what this would accomplish since we're trying to look for max area, and that involves base and height
  10. R

    Optimization of the Area of a Triangle

    Well since h=4cos2θ, couldn't we just substitute it into the expression to get sqrt(16-(4cos2θ)^2) for the base?
  11. R

    Optimization of the Area of a Triangle

    That would be cos2θ=h/4 4cos2θ=h
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    Optimization of the Area of a Triangle

    Are these labeled correctly? If those are correct, can I use the law of sines such that h/(sin90-2θ) = 4/sin90 h = 4(sin90-2θ) h=4(1-2θ) h=4-8θ
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    Optimization of the Area of a Triangle

    If I solve for h, that would give me Ccosθ-4=h. Is it ok to have an extra variable (C) in there?
  14. R

    Optimization of the Area of a Triangle

    How did you determine that angle to be 2θ? And to answer your question, I used the pythagorean theorem to find one of the side lengths
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    Optimization of the Area of a Triangle

    for convenience, I'll say c= sqrt(8h+32). Would it be correct if I said the height was c(sinθ) and the base of the largest triangle 2c(cosθ)?
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