Recent content by reklaws89

what do you mean eliminating \lambda and reducing to two equations. f_x = 2x+2\lambda f_y = 2y+\lambda f_z = 2z+2\lambda 2_\lambda = 2x+y+2z-9 and from there find the value of each and put them back into f(x,y,z)=x^2+y^+z^2

Yea, I misspoke. I meant one point with three numbers meaning a x-value, y-value, and z-value.

so you're saying that if i use f(x,y,z,\lambda) = x^2+y^2+z^2 + \lambda (2x+y+2z-9) that i will be able to find the value of each after taking partial derivatives of each variable. So would I just have three points? p.s. - Sorry!

We're suppose to minimize f(x,y,z)=x^2+y^2+z^2 subject to 2x+y+2z=9. I only ever remember learning how to do f(x,y) would it be the same equation? Thus, f(x,y,\lambda) = f(x,y) + \lambda g(x,y)? Meaning f(x,y,z,\lambda) = x^2+y^2+z^2 + \lambda (2x+y+2z-9) and then continue solving for each...

I used the equation (KE + PEg + PEs)i = (KE + PEg + PEs)f KEi=0 KEf=0 PEgi=0 PEsf=0 PEsi=1/2ky^2 (y=compression) PEgf=mg(h+y) (h=distance traveled) therefore, 1/2ky^2=mg(h+y) so 1/2(50,000N/m)(4m)^2=.1kg(9.8m/s^2)(h+2m) 100,000Nm=.98N(h+2m) 102,040m=h+2m 102,038m=h

Homework Statement Use work and energy to solve the following. A .1 kg ball is placed against a massless spring that has a stretch constant 50,000 N/m and is compressed 2 m. The spring fires the ball straight up. a) How far did the ball rise assuming no friction? b) The ball's actual rise was...