Okay, I think this problem relates with sigma notation (I'm not good at it)
the sequence given is 2, 4, 8, 16, 32 ...
It wants you to find the sum from 1-50
So the equation thing is 2^N?
How do you find all the sums again...? Thanks
Okay, so it would be 0.553 x (0.58)^X = 10^(-4) right? But you can't set it to 0 or the equation wouldn't work? So X equals like 11.6 bounces, so 12 bounces before the ball expends all of its energy?
So wait, I get the 0.146 J/M part, but what about the "(r + r2 + r3 + . . . = 2r/(1-r), r < 1)." part? Do you take 1 + 0.58 + 0.58^2 + ?
Okay it loses 0.146 J/M, and it has 0.553 Joules to start with, so 0.553 = 0.146x, so it travels 3.79 m total. Now what?
Thanks for the insight Astronuc, but how can I solve the problem now? Is there an equation that takes into account the loss of energy with each successive bounce?
ball dropped from 1 meter, ball weights 0.0564 kg. so PE = (1 m)(9.8 m/s^2)(0.0564) = 0.55272 joules. KE is 0 (since v = 0), so energy is 0.55272 joules at the top.
The ball bounces up to 0.58 meters, so its energy there is 0.3205 joules, so it loses about 2321 joules of energy.
Okay...
Can anyone help? :( I really need to understand how to do this last problem...
If my initial energy before dropping a ball was 1 joule, and the ball lost 0.3 joules on the first bounce (all the data I have), how do I figure out how many bounces it takes for the ball to lose all of its energy?
Okay, so thanks a lot Daniel. So if my initial energy was 1 joule, and the ball lost 0.3 joules of energy on the first bounce, it would take 4 total bounces until the ball stopped bouncing/exhausted all its energy? Thanks a lot, I just need 1 final answer.
Okay, if my initial energy before...
Okay, so we did a lab where we dropped a bouncy ball (mass = 56.4 g) from 1meter above the ground, and measured the height that it bounced up to.
We need to calculate the:
a) loss of energy due to the first bounce for each of the balls
b) the speed with which the ball strikes the floor...
Okay, I've got it. 100 = (9.8 + 4.5) * M
M = 6.99 Kg, so the fish has to be heavier than 6.99 Kg. But what I don't get is, why would you add 4.5 (acceleration of the line) with accel due to gravity? Thanks to all in advance.
Edit: Question #2
"A 0.145-kg baseball traveling 30.0 m/s...
I'm on the 3rd unit of my physics unit and we're applying Newton's 3 Laws of motion.
There's this problem:
"A fisherman yanks a fish out of the water with an acceleration of 4.5 m/s^2 using very light fishing line that has a "test" value of 100 N. The fisherman unfortunately loses the...
YESSSSSSSSSS
it's 12:33 eastern time right now and I can finally move on. Well this is been a monumental effort.
Having SAT prep class from 6 PM - 9PM really cuts out homework time and after 11 PM you really can't think. Thank you all that helped.
So would I be right in saying v0 = 90000 m/s and v = 0m/s?
so what does a and t stand for? My textbook really doesn't say anything about it.
t is time I think but how would i find that?