So if the no-load terminal voltage of the battery is the EMF (12.8V) this would give:
V= EMF- Ir
11.0 V = 12.8 V - 90A(r)
-1.8 V= -90Ar
.02 = r (Internal resistance)
So is this correct then?
Homework Statement
An automobile battery has a terminal voltage of 12.8 V with no load. When the starting motor (which draws 90A) is running, the terminal voltage drops to 11.0 V. What is the internal resistance of the battery?
Homework Equations
V= EMF- Ir
The Attempt at a Solution
I think...