Recent content by remedemic

When you say the "sideways" force, are you referring to the sides of the tube right after the decrease in cross sectional area that are "pushing down" on the fluid? I meant WHICH force is used to calculate the pressure (F/A). Is it the force that the fluid behind a certain point is exerting on...

Thank you so much for the reply, I'm ready to rip my hair out after trying to learn this and I very much appreciate it. I just have a couple of questions about your explanation. Although geometry has to do with it, is there not some force acting on the fluid when it crosses over the lower...

High school student here trying to learn fluids. This is not a homework question, just a concept that I am trying to grasp but can't. The picture below is in my book: The book tells me that the acceleration of the fluid after experiencing the decrease in cross sectional area is due to a...

Also, I understand that electrons are being gathered on the bottom plate (connected to the negative terminal), but could someone explain what is occurring to the top plate connected to the positive terminal?

So I'm reading that in a capacitor, an electric field is being manifested between two plates. There are no electrons actually traveling from the negative to the positive plate, correct? There is only an attraction?

Thank you gentlemen, that makes sense. I appreciate it!

I'm understanding that their purpose is to keep the pin connected to a stable potential (the ground), thus giving it a stable LOW voltage reading when the switch is not closed, but wouldn't the electric noise still affect the voltage reading, since the point at the switch closest to the pin is...

I've been studying circuitry from http://allaboutcircuits.com in hopes of experimenting with the arduino. I have read the majority of the DC volume and believe I have enough knowledge to begin working with the arduino board, however, I haven't actually built any circuits on my own yet. Are...

That was actually extremely helpful. It's pretty clear to me now. Much thanks to you sir! And thanks to skeptic as well!

So from what I'm understanding, putting the connection between the potentiometer and the return would result in zero current going into the load when the tap is at the bottom of the potentiometer, which is not a good thing? Doesn't the same thing occur when measuring voltage? In the diagram...

That's odd because in a circuit simulator, the current read by the ammeter changed with variation in the potentiometer. I suppose I'll wait for someone to clarify.

Why does the connection between the bottom of the potentiometer and the return need to be removed? Wouldn't the current change proportionately with potentiometer adjustment even if that connection was still there?

The circuit above uses a voltmeter to measure the voltage allotted to it through a potentiometer and the varying voltage acts as a signal. Could this signal system also work by measuring the current allotted to a load based off the position of the potentiometer (i.e. higher voltage = higher...

im understanding it now. Thank you very much sir.

SO, why isn't there just less current (instead of zero current) in section 2 compared to section 1 since it has more resistance? Thanks for the help by the way, I greatly appreciate it.