Recent content by renaldocoetz

took me to a world of confusion :( sheesh what am I missing? also, can one use the standard integral with the second fraction and get arc cosh [(x+2)/3] ?

well before completing the square it seemed quite clear to me that letting u= x2+ 4x -5 would make 1/2 du = x+2. for solving the 1st fraction.. but looking at the completed square i assume i should be doing something else?

that gives me a denominator of (x+2)2 - 9 ... why do we do this? also: can I split the initial fraction up into 2 separate ones? IE. (x+2) and (+1) (both over same denominator) in this way I can use substitution for the 1st fraction right? PS. sorry about the duplicate post. Realized it was...

Homework Statement Integrate: (x + 3) / sq rt of (x2 + 4x - 5) Homework Equations The Attempt at a Solution No idea. they are not derivative / integral of each other so I am not sure :( Please help asap. Thanks in advance

find the vertical (y) components of the force as well as displacement

Is this applied to the box at rest? in that case the applied force has to be greater than the max Static Friction for the box to have any acceleration.

Hi farmguy youre using the right approach but you've left out information and made a calculation error: if E0=Ef ...Initial total mechanical energy = final tot mech energy then... remember that if u make final height 0, like u did, u have to make initial height 2m. From reading the...

thats correct yeah. lucky girl

so simple :D dammit how do u know when to use these principles of conversation? its so confusing :( so by doing that i got v= -29,4 but i need angular speed. so VT = \omega r ? then i get -19,6 rad/s

no 190,44/ 4,6 = 41,4 m

190,44 devided by 4,6 = 19,6? must be something wrong with ure calculator mate :) The minusses both fall away

ure making a mistake somewhere -(13,8)^2 = + 2(-2,3)D - 190,44 = -4,6D ...now divide by (-4,6) to find D

k at the top PE is mgh... don't know the value of m though. KE is 0 at the bottom PE is 0 and KE is 1/2 mv2 but i don't know the value of m...

V2 = V02+ 2aD -(13,8)2 = + 2(-2,3)D no need to square root just calculate

K so do u agree that this is what we have now: V2 = V02 + 2aD 0 = (13,8)2 + 2(-2,3)D now calculate D