Recent content by renegade05

I have just been accepted to pursue an advanced degree (Masters) in Physics with a specialization in condensed matter. I have some questions regarding this field (Google results are somewhat outdated). (1) What exactly does a condensed matter physicist study? I know it is the study of...

Ya, see - I don't want to be rude but you are skipping some key details for me- like the part I am missing is how you are going from dE/dx = 10 MeV/cm to a range of 50cm. You say all that stuff are just constants specific to my problem. Then I wouldn't I have -dE/dx = CONSTANT. So E=Constant*x ...

Current = Charge/ Time The current given for the electron beam is 0.01 Amps The charge of an electron is 1.602X10^-19 Thus Charge/Current = Time right?

But I don't see an x in that equation, and I have no idea what beta, Tmax, I or how to use the delta function for that is. So I don't have all the values... very very confused, can you help me with step one? Just setting up the equation.

Ya I have the units for the first one. They are seconds. I am not sure what that time is referring to though or how to use it. The distance traveled will be 200pi Meters, I don't know the speed though...

Ok so for the electrons I get a time of... Time = 1.602X10^-19 / 0.01 = 1.6x10^-17 seconds ? and Distance traveled will be R=2pi*100 = 200pi NOW WHAT?!

Hmm... So what is the variable I am trying to solve for then ? I want the thickness of copper so that has an Atomic mass: 63.546, and 29 Protons - So i have my A and Z. and Tmax, I and the delta function.. What am I suppose to do with this. And even if I do plug everything in then I get...

Yes,,,, but how the heck am I suppose to use this formula?? There has to be got like a two line solution here for such a simple problem no?

Ok so Current = Charge/ Time. So I can solve for the time?! Still a very confused on how to solve this. sorry :(

Homework Statement A collider has an average electron current of 10 milliAmps and an average positron current of 5 milliAmps.If the ring radius is 100 m and there is one electron bunch and one positron bunch with uniform density, radius 1 µ and length 2 mm, what is the average luminosity in...

Homework Statement What thickness of copper is required to stop a 500 MeV/c proton? Homework Equations E=(m^2+p^2)^1/2 The Attempt at a Solution So I have been to some websites and trying to google this- and everyone is using charts and looking of the value of the range in a material...

Homework Statement Show that (Grad dot E) =0 in the dielectric of a coaxial line. (Hint: apply the divergence theorem to a portion of the dielectric.) Homework Equations Divergence theorem The Attempt at a Solution I think I need to show that grad dot E = p/epsilon = 0 I don't know - I'm...

Homework Statement A capacitor consisting of two concentric spheres is arranged so that the outer sphere can be separated and removed without disturbing the charges on either. The radius of the inner sphere is a and that of the outer sphere is b, and the charges are Q and -Q, respectively a)...

so the ground state is: \frac{-B\hbar}{2} = E and the excited state is: \frac{B\hbar}{2} = E

\frac{-B\hbar}{2}\begin{pmatrix} 0&1\\ 1&0\\ \end{pmatrix} \begin{pmatrix} a\\ b\\ \end{pmatrix}= \frac{-B\hbar}{2} \begin{pmatrix} b\\ a\\ \end{pmatrix}=E \begin{pmatrix} a\\ b\\ \end{pmatrix} So that implies: \frac{-B\hbar a}{2b} = E and \frac{-B\hbar b}{2a} = E Equating the...