Recent content by rgk13

Thank you very much!

Ahhh so essentially the HCl can react with the pyridine because the lone pair of electrons is available on the nitrogen and it can essentially interact with those electrons without effecting the aromaticity while in the second compound the lone pair is there and aromaticity is not a factor while...

so by protonating the pyrrole you would lose its stability because it would eliminate all its possible resonance structures by inducing the + charge on the nitrogen while the others still are able to resonate?

Homework Statement Pyridine and pyrrolidine react rapidly with dilute aqueous HCl to form the corresponding hydrochloride salts which are easily purified, isolated and stored in a charge. However, pyrrole, which is another nitrogen-containing heterocycle, does not form a hydrochloride salt...

You know that a very small section of the charge would be dQ. You also know that the charge Q = (lamda)*s (this was wrong under your relevant equations (the arc length of that segment)). So... dQ = (lamda)*ds using some basic trig and what not you know that ds = r*d(theta) so then you get...