It would be the left hand side that is conserved which would make:
(1/2)m_1(V^2) = (1/2)m_2(V^2) + W_nc
But what would I do after that if that is the correct equation?
-Rhaen-
The problem is as follows:
A 4.0 kg mess kit sliding on a frictionless surface explodes
into two 2.0 kg parts, one moving at 3.0 m/s, due north, and
the other at 5.0 m/s, 30 degrees north of east. (a) What is
the original speed of the...
So then the equation qould go:
0 = (1/2)mv^2 + mg(y_1-y_2) + (1/2)ky^2
0 = (.1kg)v^2 + (.2kg)(9.8)(y_1-y_2) + (49)y^2
If that is the case then how would I calculate the y distance so that I can have only the variable for velocity remaining? Thank you for your time.
-Rhaen-
Ok so far all I have been thinking I could do with part a is this...
(a)
(1/2)mv^2 + mg(y_1-y_2) = (1/2)mv^2 + mg(y_1-y_2)
This comes from the equation K_1 + U_1 = K_2 + U_2
I don't know if I am missing something in that equation though. I know that there will be cancelations, I think...
Hello all, I am looking for some assistance with a physics problem that I have for my physics class. Any help would be greatly appreciated because I have no idea where to start. Thank you all ahead of time for your help.
The problem is:
A 10-g mass is attached to the end of an...