My problem is that in free body diagram i know exactly where they are pointing. Just that depending on axes, those forces will be negative or positive. Thats why my tension is ma in the first system and -ma the second system. What I am not sure is how i am applying second law of rotation, please...
Hi. Dont coordinate axes determine their direction. The displacement X should be negative as I am moving the block down and let it do a SHM motion having the X axis pointing upward. In SHM at least in my class, they just don't matter alpha and acceleration signs. As long as it comes up like the...
My class consider the left side of the pulley has tension and the right side has instead of tension they just plug in the spring force of magnitude kx. Intuitively the spring force must be greater so there is a rotational acceleration that opposes to displacement.
Homework Statement
Determine the angular frequency of the system in the image. The cable is ideal but the pulley is not. I will present the same solution but with different coordinate axes. For some reason they arent the same and neither of them are correct.
Given data: R is the radius of...
Hmm looks like i got error in doing (4x+1)^2 and did wrong in operation. thanks everyone. No need to respond this thread anymore. It was 10x^2 -34x +12=0
It is a problem found on IB math SL book:The two perpendicular sides of a right-angled triangle have lengths x+2 and 5x-3, the hypotenuse has length 4x+1, Find X.
In the answer section, it says X is either 2/5 or 3.
I tried a lot, -> i arrived to 10x^2 - 18x -12= 0
Later i used quadractic...
I understand obviously that the image and light will be kept but it will become a little bit green. But what happen in a very specific way especially about absorption??