Recent content by rick906

  1. R

    Does the Integral Test Result Indicate the Series Sum?

    Thanks for the fast reply dude! If that number is not the sum, does it represent something? (just outta curiosity) Thank you
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    Does the Integral Test Result Indicate the Series Sum?

    Hi all, I just want to know a little something: When doing the integral test in order to find a sum, when might get a result (integral) of a certain number. As we know, getting a number as result an integral test means that this serie converges...but does that mean that the serie converges to...
    • rick906
    • Thread
    • Integral Integral test Test
    • Replies: 3
    • Forum: Calculus
  3. R

    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Thank you, I was really worried about this problem, now I feel better :) I'd like to thank everyone for helping me solving this problem (which doesn't look hard anymore). Hope that I'll be able to help other people on this forum.
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    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Thanks dude! Just one thing: you said you 'Thought' it was correct... did you mean you 'think' it's correct or that you thought it was but then you noticed a mistake? Lol, I know it was linearly presented, but usually it just ain't that way... I made an effort of presentation on this one...
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    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Can anybody just check my solution and tell me if all the steps are OK or if there is a mistake somewhere...and of course check the result... please Thanks :wink:
  6. R

    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Therefore, it's right (for my level of knowledge, at least) just to say that Sum of 1/n (and n power of something smaller than 1) diverges? Count Iblis, I would have done what you are saying if I had understood it :smile: In fact, I don`t know that zeta series quite well now (learned about it...
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    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Thanks, it confirms that this is something we haven`t learned (not yet, anyway). I find something strange with the Riemann zeta function: it says that: \zeta(1) = infinity ok we know this one because it's the harmonic serie (p`s equal or smaller than 1 diverge) but...
  8. R

    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Well, yes, I only wanted to know if it converges. I wonder how you knew it from the beginning...maybe something I have not learned yet... By the way, I really do not understand those signs... maybe this is the notion I do not know. Anyway, are my steps and my result right? Thanks again dudes.
  9. R

    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Ouhhh It's so true. I had totally forgotten that p-series with p>1 converges (I thought it was the opposite!) So I think the problem is solve thanks to you all (especially Vid) and I've scanned the problem, if anyone could just check if everything's alright, it'd be really great (attachment)...
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    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Hi back Ouh, I was so nervous that I forgot to mention : yes, I'd like to know if the sum converges or diverges. As for CRGreathouse, I haven't learned that technic, so I'm not sure if the teacher will allow me to use it in a test. Vid says I've tried it many times, can you please tell...
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    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Oh sorry,it is a sum, not an integral, I don't know why I put x instead of n. I'm not sure to understand what you people mean by 'integrate and then apply the sum' Technics I have learned for solving a sum are : Reinman (p-series), the integral test, comparision test, ratio test, the n^th...
  12. R

    Sum(from 1 to infinity) of 8 / x^2(4+ln(x))

    Hi all, I'm stuck on this problem, I can't solve it :confused: Sum(from 1 to infinity) of 8 / x^2(4+ln(x)) Does anybody have the fainest idea of how to solve? Thanks all
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