Recent content by ricof

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    Closed system piston cylinder device problem

    Sorry, 'Oh' as in the figure of speech. So I use ideal gas law with the same P but different V each time to find the temperatures? What does degree of freedom mean? I haven't heard of that before.
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    Closed system piston cylinder device problem

    Homework Statement A closed system comprising a cylinder and frictionless piston contains 1kg of a perfect gas of which molecular mass is 26. The piston is loaded so that the pressure is constant at 200kPa. Heat is supplied causing the gas to expand from 0.5m^3 to 1m^3. Calculate heat...
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    Entropy of gas at constant pressure and volume

    I used T2/T1 = (P2/P2)^(n-1/n) and n = Cp/Cv
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    Entropy of gas at constant pressure and volume

    Homework Statement 1m^3 of air is heated reversibly at constant pressure from 288K to 573K. Then it is cooled reversibly at constant volume back to the initial T. Initial P is 103kPa Calculate overall change in entropy. Cp=1.02 Cv=0.702 Homework Equations dS=Cp x ln(T2/T1)-R x...
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    Change in entropy in a polytropic process

    Thanks, have now got the answer
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    Change in entropy in a polytropic process

    The atomic weight of nitrogen is 7 but as it is diatomic, the molecular weight is 7x2 = 14. So 1.2kgs represents 1200/14= 85.7 moles = n?
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    Change in entropy in a polytropic process

    In your previous post you mentioned the ideal gas law which is PV=nRT no? n is the number of moles so I think you use the mass of the nitrogen (1.2kg) in there somewhere?
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    Change in entropy in a polytropic process

    Oh right ok so 120kPa x V = 1.2 x R x 300K As the gas is Nitrogen do I still use R=8.314?
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    Change in entropy in a polytropic process

    I should add that I have absolutely no idea where or how the 1.2kg of nitrogen comes into the equation, nor if V1 is in fact 1. Please help me I've been staring at this one for hours!
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    Change in entropy in a polytropic process

    Homework Statement A piston cylinder device contains 1.2kg of nitrogen at 120kPa and 300K. Gas is compressed slowly in a polytropic process during which PV^1.3 = constant. The proces ends when the volume is reduced by one half. What is the entropy change? Homework Equations (P2/P1) =...
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    Change in entropy at constant temperature

    Ok, so as dE = 0, Q = -W and as PV = nRT, -W=PV ln (v1/v2) which is Q Thanks guys, my answer is correct. Thanks for helping!
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    Change in entropy at constant temperature

    Because T is constant, there is no change in internal energy right? And also, in the above equation for isothermal expansion, how is n calculated?
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    Change in entropy at constant temperature

    Homework Statement Calculate the entropy change when 0.011m3 of a perfect gas at a constant temperature of 273K is compressed from an initial pressure 1x10^5 N/m/m to a pressure of 1x10^6 N/m/m. I know the equation but cannot work out Q! Please help! Homework Equations dS=Q/T The...
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