Recent content by Rival

  1. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    hehe, that could help if i looked for the right thing. Thanks alot, i really appreciate your help. Kevin:smile:
  2. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    now that i know the mol wt, i matched it with the periodic table and it comes out to Co, but which one of the choices are Co.
  3. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    so using the equation you gave me, i have n = 5 and g = 135, so i find Mo, which came out to be 27, and in the periodic table 27 is Co. what element is Co? but i think its wrong...
  4. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    ok so we have 5 moles but now what? how do we figure out what element it is?
  5. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    ok so i am guessing that the equation that i need to use is n=N/NA but how do we figure out N?
  6. R

    What is this element, carbon, hydrogen, oxyden or aluminum?

    8. [CJ6 14.P.001.] A mass of 135 g of an element is known to contain 30.1 1023 atoms. What is the element? carbon hydrogen oxyden aluminum This is the question on my Physics practice test for my exam tomorrow. i don't know where to even begin with this one. we haven't really gone over...
  7. R

    Translational/gravitational/elastic/total energy problem

    A 1.80 kg object is hanging from the end of a vertical spring. The spring constant is 34.0 N/m. The object is pulled 0.200 m downward and released from rest. Complete the table below by calculating the translational kinetic energy, the gravitational potential energy, the elastic potential...
  8. R

    Cylinder fitted with piston and spring im lost

    changes have been made...all units have been placed in the appropriate places for my answers kevin:wink:
  9. R

    Cylinder fitted with piston and spring im lost

    why yes i can evaluate that integral, or at least i better be able to. seeing how i have finished diff E.Q. last quarter... anyways the equation is just 1/2kx^2 so i have .5(2900)(.058)^2= 4.8778J thanks again...definitly a confidence booster right there =) Kevin
  10. R

    Cylinder fitted with piston and spring im lost

    so is it just the kinetic energy in the spring? KE=1/2Mv^2? Kevin
  11. R

    Cylinder fitted with piston and spring im lost

    Ah ha! i have F=kx as my equation...F=force pushing down on cylinder and spring F=168.4N k=2900N F/k=x x=.058m ok first part done but still stuck on second part kevin... P.S. thanks everyone and especially Warren
  12. R

    Cylinder fitted with piston and spring im lost

    well if i draw a free body diagram of the piston, i will get a force pushing down which would be Atmospheric pressure multiplied by area which is just (pi)(r^2) or in Newtons 168.4. now i sitll have a force of 2900 Newtons pushing up from the spring, correct? or am i wrong there kevin
  13. R

    Cylinder fitted with piston and spring im lost

    A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open at the top. Friction is absent. The spring constant of the spring is 2900 N/m. The piston has a negligible mass and a radius of 0.023 m. (a) When air beneath the piston is completely pumped...
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