Recent content by rjr

Define the function h(x) as: h(x)=\frac{sin(4x)}{2x} Try to evaluate this function at zero (i.e. f(0) = ?). You will obtain: f(0)=\frac{sin(0)}{0} f(0)=\frac{0}{0} → if a function comes out to be "0/0" we call this "indeterminate form", which means that we can use L'Hopital's rule for...

gopher_p is correct: using the log law loga x2 = 2loga x does make for easier computation. however, if you set u = loga x2 then your equation would become y = u2 so then, y'(x) = du/dx * 2u the only "tricky" part is finding du/dx, but as S.R mentioned, you can just use the change of base...

pasmith has the best response so far...just to expand a bit though... In order to solve the first order linear nonhomogenous differential equation: y'(x) + P(x)y(x) = Q(x) , you do have to solve the homogenous form of this equation, but in a slightly different way - let me explain by using...

nothing wrong with the u-substitution and integration, however on the right side toward the bottom of your page, one step reads: 1/w = 2/(cos(Θ2)) + C What I suggest: 1). ALWAYS isolate the function variable first (in this case w(Θ)) before solving for the arbitrary constant (in this case C)...