Recent content by rkslperez04

Gotcha.. I did take it a step farther in my notes.. didnt post it here by mistake.. but we had to move variables around solve for what the question was asking for. thanks for walking me through this :)

okk.. I think I get it We are dealing with nothing but Potential engery and the work along the string, soo... PE = PE - W

ok.. The frictional force on the beads will actually change the KE making it slower or faster depending on how much friction is applied. Since the bead comes to a rest lower then the initail position.. the friction must be high.. so how much work is being done on the bead to slow it down. am...

ok.. I think i got it...Its soo funny.. I would never think of this during the winter... usually you just sled and go.. not caculate and go..LOL I guess in a sled race.. this is all very important (50)(10) - (50)(2.5) / 2.5 = 500 - 125 / 2.5 = 150 <~~ wieght of cart

if you push on a wall and nothing happens then the Forces were equal, if your Work applied to the wall overcomes the Force you bust through it like superman. and the bead starts and stops... then start & stop KE + PE = KE + PE 0 + mgh1 = 1/2mv^2 + mgh2 ? I bet am I...

ok... this is the formula I have m1v1i + m2v2i = (m1 + m2)vf ----- I take it they are asking for the m2 and m2v2i willl cancel out being v2i = rest which is 0. So do I pull everything to oneside and solve for m2 m2 = (m1 + m2)vf - m1v1i / v2i I think I am doing something wrong

am I showing in notes from that this may be an inelastic collision (m1v1i + m2v2i = (m1 + m2)Vf)... sorry I am not help to you :(

I need a nudge in the right direction. A 50-kg boy runs at a speed of 10.0 m/s and jumps onto a cart originally at rest. The cart, with the boy on it, then takes off in them same direction in which the boy was running. If the cart with the boy has a veolocity of 2.50 m/s, what is the mass of...

would it be? KE + PE = KE + PE and go from there?

Hey guys, I must be misunderstanding what the work engery therom is.. I took it to be Wt= 1/2mvf^2 - 1/2mvi^2 I don't have a velicity though? I know the 50 cm and 30 cm come in somewhere but how would any of that give me friction?

ok... gotcha... let me go work it out... :)

Hey there, I need a nudge in the right direction on two problems. Can you anyone help me out. I will post the other question seperately in a few :) Here we go: 1) A bead is sliding along a stiff wire track. The bead is released from rest at point A and comes to a stop (momentarily)...

ohh.. I see.. the second hill is 15m high.. i apolize for that. Does my work look right?

LOL.. I thought the same thing about this question.. as with most..LOL That was the entire question. You can see my fret over this problem.. With the decimals places I would say 10.0 instead of 10 ?? Looks good though??

Bare with me guys as I enlist your help through this worksheet. I really want to get a good grade on this upcoming test and this worksheet is our study guide. I think I have the hang off it but I want to make sure I am grasping the questions here. A rollar coaster is traveling on a...