Recent content by road_king

Hi, I am only want to raise a last thought. It is clear that the maximum current is going to be at the start up of the motor. In my application I am going to put the motor into a sequence of successive starts and stops, changes of direction ...etc. If I permit 3A to be the current limit...

Thanks fellows, my major concern is that in my application the motor is not going to rotate at a set regime, but it is going to do a sequence of starts-stops-changes of directions, whatever it needs to balance the pendulum, or at the swing up.. the time it takes to get it up. So I am not...

Thank you very much, Uart. Your help is very appreciated. Actually the control law is in terms of Voltage, and as far as I am reading more about Dc motors, I am leaning towards to limit the current up to 1A (and not to 3A), just for being preventive. The controller is going to take longer to...

I am asking this because this DC motor is the actuator in an Inverted Pendulum control system. The Pendulum rotates freely over a pivot which is mounted over a cart, which moves along a rack as well. So the manner to control the movement of the cart is to supply a voltage signal to the motor...

If in the DC motor specs doc says that it can handle + - 16 Volts maximum and 3A of peak current but the nominal voltage is 6 V and the continuous current is 1A... it means that it is safe if you feed it with 3A during the time of start up? Supposedly it is only meant to be at the start...

Thanks guys, LabVIEW has a lot of integration routines, I was thinking of trying a variable step size Runge-Kutta.

Sorry if I might not be as clear as I should be. I have this program in which I have to set the proper units of the dimensions of the problem in order to minimize the error that the simulation is going to produce. I read a paper in which it states that if the variables only vary from -1 to +1...

Homework Statement Hi, I have to do a simulation of two non linear dynamical equations which represent a electromechanical system. (An inverted pendulum attached to a cart moving over a rail). I am going to simulate the response via numerical methods programmed in LV. (I am trying firts with a...

That does not make sense to me. The KE of the pendulum is measured relative to the ground because ##\dot x + l \cos\theta\, \dot \theta## ... ##\dot x## express movement relative to the ground. (Plus the rotation relative to the cart).. Please shed some light..

Anyone knows the proper way to assign the initial conditions for the first order derivatives to the Series function??

Thank you both very much! It was the problem. (My misconception of what Mathematica undertood as variables... ) I put the expression in a explicit dependency of time form and It seems to work, although It was not linear at all ... ? I don't know why. I add this: Normal[Series[f1[x...

Thank you very much! That is exactly in the same syntax form I wrote. I will copy/paste but I think it will be useless [SIZE="1"]f[x_, \[Theta]_, \[Alpha]_, vm_] := ((1/(rm*rmp^2))*(7*(js + h^2*(mc + mp)) - 3*h^2*mp*Cos[\[Alpha][t]]^2 - 3*h*mp*Sin[2*\[Alpha][t]]*x[t] + (7*(mc + mp) -...

Thank you very much Jackmell. That is basically the idea, but my function f is much more complicated than that. That is why it would be a very tedious work to write it in Latex. I tried to export it with Mathematica function, but I have not got pretty satisfactory results. So, let´s focus...

Hi! I'm trying to linearize a function f which is dependent of 4 variables, each one dependent of time. f[var1_,var2_,var3_,var4_]:= ... expression I use Series[f, {var1,var10 ,1},{var2,var20 ,1},...] syntax as I read on the documentation center. The problem is that the program...

I tried to improve the notebook file, I hope it will be more friendly!