I was rearanging it again last night since the new arrangement didn't seem right either.
h = \frac{1}{2} \frac {mv^{2}}{mg}
I noticed that I had mv^2 on the bottom, but it should be on the top, while dividing by mg.
Ok, that makes sense. Makes part B easy to find h in part A.
So I want to rearrange \frac{1}{2}mv^{2} = mgh to
h = \frac{1}{2} \frac {mg}{mv^{2}}
So mass will cancel out, leaving me with the known variables. If that is the correct rearranged form, I know enough trig to solve for part...
Homework Statement
You've skied down a slope and are going 20m/s when you hit the base of a slope that is 30 degree incline.?
Assuming friction and drag are negligible, how much altitude (y) will you gain as you’re slowing down?
How far up the 30 degree slope (∆x along the incline) will...