Recent content by robbyrandhawa

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    Rotational Motion Homework: Mass 12 kg Rod, Pivot Friction-Free

    i just realized how can i find inertia (I) at a because i don't know what Torque is …. i worked something out and both torque and I were 12 :S that looks wrong
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    Rotational Motion Homework: Mass 12 kg Rod, Pivot Friction-Free

    I=mr^2 and Torque=Ia(angular)… you saying to use these. If i find I(inertia) at point a then i use that and find angular acceleration at B? is that what your hinting towards?
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    Rotational Motion Homework: Mass 12 kg Rod, Pivot Friction-Free

    Homework Statement Consider a uniform rod of mass 12 kg and length 1.0 m. At its end, the rod is attached to a fixed, fricition free pivot. initially the rod is balanced vertically abbove the pivot and begins to fall (from rest) as shown. Determine a) the angual acceleration of the rod as...
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    A 470g firework is traveling straight up at 13 m/s

    sorry scratch the previous msg so i found the vertical and horizontal V's of the other piece and then using pythagorean theorem i find the overall V correct? 1) horizontal: pinitial=0=m1v1+m2v2 --> v2 = -9.375 2) vertical: pinitial = 6.11N = m2v2 (p1=0) ---> v2=19.0 3) pythagorean theorem: v2...
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    A light string is wrapped around a solid cylinder

    so i have to use t=rF and I=1/2mr^2 and then solve for m??
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    A 470g firework is traveling straight up at 13 m/s

    okay so i would find the horizontal and vertical V of the other piece and then using pythagorean theorem find the final v for the other piece? correct? 1) horizonal: m1v1=m2v2 = 0.15(20)=0.32v2 2) vertical = 0 3) pythagorean theorem correct?
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    A light string is wrapped around a solid cylinder

    Homework Statement a light string is wrapped around a solid cylinder and a 300 g mass hangs from the free end of the string. When released, the max falls a distance 54 cm in 3.0s. b) calculate tension in string c) calculate mass of cylinder Homework Equations F=ma I=1/2(mr^2)...
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    A 470g firework is traveling straight up at 13 m/s

    Homework Statement a 470 g firework is traveling straight up at 13 m/s when it explodes into two pieces. The smaller piece (150 g ) shoots off horizontally towards the East at 20 m/s. Find the speed and direction of the other piece directly after the explosion. Homework Equations...
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    Uniform circular motion and tension of a string

    w = 2pi(r)/T is that the formula you are talking about?
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    Uniform circular motion and tension of a string

    when u look at the image, theta =53 is close to the vertical component, so Fnvertical = a/h = cos 53 to find the vertical component the angle is adjacent to the vertical side that's why it is cos.
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    Uniform circular motion and tension of a string

    yes... not sure I am quite following you.
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