i just realized how can i find inertia (I) at a because i don't know what Torque is ….
i worked something out and both torque and I were 12 :S that looks wrong
I=mr^2 and Torque=Ia(angular)… you saying to use these. If i find I(inertia) at point a then i use that and find angular acceleration at B? is that what your hinting towards?
Homework Statement
Consider a uniform rod of mass 12 kg and length 1.0 m. At its end, the rod is attached to a fixed, fricition free pivot. initially the rod is balanced vertically abbove the pivot and begins to fall (from rest) as shown. Determine
a) the angual acceleration of the rod as...
sorry scratch the previous msg so i found the vertical and horizontal V's of the other piece and then using pythagorean theorem i find the overall V correct?
1) horizontal: pinitial=0=m1v1+m2v2 --> v2 = -9.375
2) vertical: pinitial = 6.11N = m2v2 (p1=0) ---> v2=19.0
3) pythagorean theorem: v2...
okay so i would find the horizontal and vertical V of the other piece and then using pythagorean theorem find the final v for the other piece? correct?
1) horizonal: m1v1=m2v2 = 0.15(20)=0.32v2
2) vertical = 0
3) pythagorean theorem
correct?
Homework Statement
a light string is wrapped around a solid cylinder and a 300 g mass hangs from the free end of the string. When released, the max falls a distance 54 cm in 3.0s.
b) calculate tension in string
c) calculate mass of cylinder
Homework Equations
F=ma
I=1/2(mr^2)...
Homework Statement
a 470 g firework is traveling straight up at 13 m/s when it explodes into two pieces. The smaller piece (150 g ) shoots off horizontally towards the East at 20 m/s. Find the speed and direction of the other piece directly after the explosion.
Homework Equations...
when u look at the image, theta =53 is close to the vertical component, so Fnvertical = a/h = cos 53
to find the vertical component the angle is adjacent to the vertical side that's why it is cos.