Recent content by Robert IL

I'm sorry, but I'm not familiar with the term "unique extension" what do you mean by that?

Since I=irrationals are uncountable and so are reals I guess we could create a bijection between the two (not sure if I am correct here), but I suppose I would be mapped to R.

Yes, Q=rationals, R=reals; but how and why is mapping of Q to Q relevant here, since I am later asked about map of function R to R?

Let f: R\rightarrowR be a non-decreasing function. Suppose that f maps Q to Q and f: Q\rightarrowQ bijection. Prove that f: R\rightarrowR is continuous, one to one and onto. Hello everyone, I have been staring at this statement for a while now and I just don't understand it, hence I can't...