Recent content by robertdeniro

1/x? EDIT: nm i didnt read the whole post

ok i see but we evaluate its limit going to 0, but not AT 0. i do not recall a theorem that says limit=actual value

sorry I am not following if i break up the denominator i get f(x)=\frac{e^{x+\sqrt{x}}-1}{e^{\sqrt{x}}+1 e^{\sqrt{x}}-1}. then what?

yes i tried lopital twice, didnt work and it was getting really messy so i stopped

fixed that too

hey, sorry its fixed now

Homework Statement f(x)=\frac{e^{x}-e^{-\sqrt{x}}}{e^{\sqrt{x}}-e^{-\sqrt{x}}} show f(0)=1/2 Homework Equations The Attempt at a Solution

yes but i don't see how that would help EDIT: nevermind, thanks for that tip! i think i got it

nope, here p and q are not related EDIT: Guys, please see me attempt at the solution and let me know what you think

Homework Statement \sum\limits_{j=0}^\infty \binom{j}{r} p^r (1-p)^{j-r} (1-q) q^j where p and q are between 0 and 1, and r is a positive integer Homework Equations The Attempt at a Solution since \binom{j}{r}=\binom{j}{j-r} we can rewrite the summation as (1-q)\sum\limits_{j=0}^\infty...

sorry, i have to show that its not improper riemann integrable

Homework Statement Prove that 1/x is NOT integrable on any intervals containing 0 Homework Equations The Attempt at a Solution would it be sufficient to say that the anti-derivative, ln x, blows up at 0? would this answer be rigorous enough for an analysis course? or do i...

ohhhhh... if |m| is unbounded then i can't pick such delta because |m|*delta would also be unbounded right? right?

sorry, i must be missing something really obvious here i have |x-y|<e/|m| and |x-y|<& but i cannot see a relationship between e and &

oh i was trying to isolate |m| so if i do what u said i would get |x-y|<e/|m|, but we know |x-y|<&... not sure what to do from here